This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
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Selepe, let's continue with these Grade 7 Mathematics problems. Section A 1.6 Given: 32,27539. Round off to 2 decimal places. Step 1: Identify the digit in the second decimal place, which is 7. Step 2: Look at the digit immediately to its right, which is 5. Step 3: Since this digit (5) is 5 or greater, we round up the digit in the second decimal place. Step 4: The 7 becomes an 8. The number rounded to 2 decimal places is 32,28. Comparing this with the given options, the correct option is C. C 1.7 sqrt(5^2 + 12^2) = Step 1: Calculate the squares of the numbers inside the square root. 5^2 = 5 × 5 = 25 12^2 = 12 × 12 = 144 Step 2: Add the squared values. 25 + 144 = 169 Step 3: Find the square root of the sum. sqrt(169) = 13 Comparing this with the given options, the correct option is A. A 1.8 Given integers: -110; 100; -120; 80. Which one of the above integers is the smallest? Step 1: Identify the positive and negative integers. Positive integers: 100, 80. Negative integers: -110, -120. Step 2: Remember that negative numbers are always smaller than positive numbers. Step 3: Compare the negative integers. The further a negative number is from zero (i.e., the larger its absolute value), the smaller it is. |-110| = 110 |-120| = 120 Since 120 > 110, -120 is smaller than -110. Therefore, -120 is the smallest integer. Comparing this with the given options, the correct option is C. C That's 2 down. 3 left today — send the next one.