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6 Given: 32,27539. Round off to 2 decimal places. 1.7 sqrt(52 + 122) = 1.8 −110; 100; -120; 80 Which one of the above integers is the smallest?

Mathematics

ScanSolve AI Answer

Answer

C

Step-by-step solution

10 steps

Selepe, let's continue with these Grade 7 Mathematics problems.

Section A

Part 1.6· 4 steps

Given: 32,27539. Round off to 2 decimal places.

  1. Identify the digit in the second decimal place, which is 7.

  2. Look at the digit immediately to its right, which is 5.

  3. Since this digit (5) is 5 or greater, we round up the digit in the second decimal place.

  4. The 7 becomes an 8.

    The number rounded to 2 decimal places is 32,28.

    Comparing this with the given options, the correct option is C.

    C\boxed{\text{C}}

Part 1.7· 3 steps

52+122=\sqrt{5^2 + 12^2} =

  1. Calculate the squares of the numbers inside the square root.

    52=5×5=255^2 = 5 \times 5 = 25 122=12×12=14412^2 = 12 \times 12 = 144
  2. Add the squared values.

    25+144=16925 + 144 = 169
  3. Find the square root of the sum.

    169=13\sqrt{169} = 13

    Comparing this with the given options, the correct option is A.

    A\boxed{\text{A}}

Part 1.8· 3 steps

Given integers: −110-110; 100; −120-120; 80. Which one of the above integers is the smallest?

  1. Identify the positive and negative integers.

    Positive integers: 100, 80.
    Negative integers: −110-110, −120-120.

  2. Remember that negative numbers are always smaller than positive numbers.

  3. Compare the negative integers.

    The further a negative number is from zero (i.e., the larger its absolute value), the smaller it is.

    ∣−110∣=110|-110| = 110 ∣−120∣=120|-120| = 120

    Since 120>110120 > 110, −120-120 is smaller than −110-110.

    Therefore, −120-120 is the smallest integer.

    Comparing this with the given options, the correct option is C.

    C\boxed{\text{C}}
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