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7.1 Identify two mathematical errors in the learner's reasoning and correct each one. 1.7.2 Write corrective feedback suitable for a Grade 6 learner. Your feedback must include one concrete representation or teaching move, such as a table, graph, number line, or balance approach.

Mathematics

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Answer

20
Graph of C(n) = 6n + 30

Use the left and right arrow keys to trace the curve, up and down to jump between key points, and plus and minus to zoom.

Key points of C(n) = 6n + 30
Pointny
x-intercept−50
y-intercept030

Here are the solutions for questions 1.7.1 and 1.7.2:

1.7.1 Identify two mathematical errors in the learner's reasoning and correct each one.

  • Error 1: Misunderstanding of Proportionality

    • Learner's reasoning: "Because this is a straight-line graph, it is proportional."
    • Correction: A relationship is proportional only if its graph is a straight line that passes through the origin (0,0)(0,0). The cost function C(n)=6n+30C(n) = 6n + 30 is a straight line, but it does not pass through the origin (it passes through (0,30)(0,30)). Therefore, it is a linear relationship, but not a proportional one.
  • Error 2: Arithmetic Error in Solving the Equation

    • Learner's reasoning: The learner correctly reached 4n=804n = 80 but then incorrectly concluded n=5n=5.
    • Correction: To solve 4n=804n = 80, you must divide both sides by 4. 4n=804n = 80 4n4=804\frac{4n}{4} = \frac{80}{4} n=20n = \boxed{20} The learner incorrectly divided 20 by 4, or made an arithmetic error in dividing 80 by 4.

1.7.2 Write corrective feedback suitable for a Grade 6 learner. Your feedback must include one concrete representation or teaching move, such as a table, graph, number line, or balance approach.

"Great job setting up the equation to find the number of packs! Let's look at two things.

First, about straight lines and proportionality: A straight line is only proportional if it starts at zero. Think about the cost function C(n)=6n+30C(n) = 6n + 30. If you print 0 packs, the cost is R30 (the setup fee). Since the cost isn't R0 when you have 0 packs, it's a straight line, but not a proportional one.

Second, when you had 4n=804n = 80, you need to find what one 'n' is. Imagine you have a balance scale:

Left side: 4×nRight side: 80\text{Left side: } 4 \times n \quad \text{Right side: } 80

To find out what one 'n' is, you need to divide both sides by 4 to keep the scale balanced:

4n4=804\frac{4n}{4} = \frac{80}{4}

So, nn should be 20\boxed{20}, not 5. This means the club needs to sell 20 packs to make R50 profit."

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