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Explain 7 + 6 by 'decomposition of addend' and 'decomposition of augend' by making group of 10.

Mathematics

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2 parts
a
13
b
13

Step-by-step solution

9 steps

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3 Confirm

2) Explain 7+67 + 6 by 'decomposition of addend' and 'decomposition of augend' by making group of 10.

Part a· 3 steps

Decomposition of addend (decomposing 6)

In the expression 7+67 + 6, 7 is the augend and 6 is the addend. We will decompose the addend 6.

  1. Decompose 6 into 3 and 3 to make 10 with 7.

    7+6=7+(3+3)7 + 6 = 7 + (3 + 3)

  2. Group 7 and 3 to make 10.

    (7+3)+3=10+3(7 + 3) + 3 = 10 + 3

  3. Add 10 and 3.

    10+3=1310 + 3 = \boxed{13}

Part b13

Decomposition of augend (decomposing 7)

In the expression 7+67 + 6, 7 is the augend and 6 is the addend. We will decompose the augend 7.

  1. Decompose 7 into 4 and 3 to make 10 with 6.

    7+6=(4+3)+67 + 6 = (4 + 3) + 6

  2. Group 6 and 4 to make 10.

    4+(3+6)=4+(6+3)=(4+6)+3=10+34 + (3 + 6) = 4 + (6 + 3) = (4 + 6) + 3 = 10 + 3

  3. Add 10 and 3.

    10+3=1310 + 3 = \boxed{13}

    4 Practice

    1) Read the Grade 3 textbook (p. 10-11) and do all exercises.
    As an AI, I cannot read physical textbooks or complete exercises from them.

    2) Read teacher's manual (p.14-15) to understand how to teach it.
    As an AI, I cannot read physical manuals.

    3) Practice demonstrating the solving of addition by using 'make 10'.
    Let's demonstrate solving 8+58 + 5 using the 'make 10' strategy.

  4. Decompose one of the numbers to make 10 with the other.

    We can decompose 5 into 2 and 3.

    8+5=8+(2+3)8 + 5 = 8 + (2 + 3)

  5. Add 8 and 2 to make 10.

    (8+2)+3=10+3(8 + 2) + 3 = 10 + 3

  6. Add 10 and 3.

    10+3=1310 + 3 = \boxed{13}
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