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A 30 m, 36 m, and 84 m wire are to be cut into equal pieces. What is the least number of pieces the wires can be cut into?

Mathematics

ScanSolve AI Answer

Answer

25 pieces25 \text{ pieces}

Step-by-step solution

3 steps

Here's the solution for number 18.

18)

  1. Find the greatest common divisor (G.C.D.) of the lengths of the three wires (30 m, 36 m, and 84 m).

    This will be the length of the longest possible equal pieces.
    Prime factorization of each length:

    30=2×3×530 = 2 \times 3 \times 5 36=22×3236 = 2^2 \times 3^2 84=22×3×784 = 2^2 \times 3 \times 7

    The common prime factors are 2 and 3.
    The lowest power of 2 is 212^1.
    The lowest power of 3 is 313^1.

    G.C.D.=21×31=2×3=6\text{G.C.D.} = 2^1 \times 3^1 = 2 \times 3 = 6

    So, each piece of wire will be 6 meters long.

  2. Calculate the number of pieces obtained from each wire.

    Number of pieces from the 30 m wire = 306=5\frac{30}{6} = 5 pieces
    Number of pieces from the 36 m wire = 366=6\frac{36}{6} = 6 pieces
    Number of pieces from the 84 m wire = 846=14\frac{84}{6} = 14 pieces

  3. Calculate the total least number of pieces.

    Total pieces = 5+6+14=255 + 6 + 14 = 25 pieces

    25 pieces25 \text{ pieces}
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