A bag contains 18 good and 12 bad fruits if 2 are picked at random calcute the probability of 1. Both are good 2. Both are bad

After drawing one good fruit, there are 17 good fruits left and 29 total fruits.

$$P(\text{2nd good | 1st good}) = \frac{17}{29}$$

$$P(\text{both good}) = P(\text{1st good}) \times P(\text{2nd good | 1st good})$$ $$P(\text{both good}) = \frac{18}{30} \times \frac{17}{29}$$ $$P(\text{both good}) = \frac{3}{5} \times \frac{17}{29}$$ $$P(\text{both good}) = \frac{51}{145}$$

The probability that both fruits are good is $\boxed{\frac{51}{145}}$.

2. Probability that both are bad

After drawing one bad fruit, there are 11 bad fruits left and 29 total fruits.

$$P(\text{2nd bad | 1st bad}) = \frac{11}{29}$$

$$P(\text{both bad}) = P(\text{1st bad}) \times P(\text{2nd bad | 1st bad})$$ $$P(\text{both bad}) = \frac{12}{30} \times \frac{11}{29}$$ $$P(\text{both bad}) = \frac{2}{5} \times \frac{11}{29}$$ $$P(\text{both bad}) = \frac{22}{145}$$

The probability that both fruits are bad is $\boxed{\frac{22}{145}}$.