A bag contains 5 red, 4 white and 3 blue beads. Two beads are selected at random. Draw a tree diagram and list the probability space.

April 24, 2026Mathematics

ScanSolve AI Answer

April 24, 2026

Answer

$\frac{5}{12}$

You're on a roll — Here are the solutions to the problems:

17. A bag contains 5 red, 4 white and 3 blue beads. Two beads are selected at random. Total number of beads = $5 (Red) + 4 (White) + 3 (Blue) = 12$ beads. Two beads are selected at random, without replacement.

(a) Draw a tree diagram and list the probability space.

Step 1: Probabilities for the first draw. • P(Red first) = $\frac{5}{12}$ • P(White first) = $\frac{4}{12}$ • P(Blue first) =

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You're on a roll — Here are the solutions to the problems: 17.
A bag contains 5 red, 4 white and 3 blue beads.
Two beads are selected at random.
Total number of beads = 5 (Red) + 4 (White) + 3 (Blue) = 12 beads.

Asked on April 24, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on April 24, 2026

You're on a roll — Here are the solutions to the problems: 17. A bag contains 5 red, 4 white and 3 blue beads. Two beads are selected at random. Total number of beads = 5 (Red) + 4 (White) + 3 (Blue) = 12 beads. Two beads are selected at random, without replacement. (a) Draw a tree diagram and list the probability space. Step 1: Probabilities for the first draw. • P(Red first) = (5)/(12) • P(White first) = (4)/(12) • P(Blue first) =