A bat and ball cost 1.10 dollars total. The bat costs 1 dollar more than the ball. How much is the ball?

The ball costs 0.05 dollars. Steps: 1. Let B be the cost of the bat and L be the cost of the ball. 2. From the problem, we have two equations: B + L = 1.10 (Total cost); B = L + 1 (Bat costs 1 dollar more than the ball) 3. Substitute the second equation into the first equation: (L + 1) + L = 1.10 4. Combine like terms: 2L + 1 = 1.10 5. Subtract 1 from both sides: 2L = 1.10 − 1; 2L = 0.10 6. Divide by 2 to solve for L: L = 0.10 / 2; L = 0.05 Therefore, the ball costs 0.05 dollars.

A bat and ball cost 1.10 dollars total. The bat costs 1 dollar more than the ball. How much is the ball?

The ball costs 0.05 dollars. Steps: 1. Let B be the cost of the bat and L be the cost of the ball. 2. From the problem, we have two equations: B + L = 1.10 (Total cost); B = L + 1 (Bat costs 1 dollar more than the ball) 3. Substitute the second equation into the first equation: (L + 1) + L = 1.10 4. Combine like terms: 2L + 1 = 1.10 5. Subtract 1 from both sides: 2L = 1.10 − 1; 2L = 0.10 6. Divide by 2 to solve for L: L = 0.10 / 2; L = 0.05 Therefore, the ball costs 0.05 dollars.

Solved: A bat and ball cost 1.10 dollars total. The bat…

Steps:

Let B be the cost of the bat and L be the cost of the ball.
From the problem, we have two equations:
- B + L = 1.10 (Total cost)
- B = L + 1 (Bat costs 1 dollar more than the ball)
Substitute the second equation into the first equation: (L + 1) + L = 1.10
Combine like terms: 2L + 1 = 1.10
Subtract 1 from both sides: 2L = 1.10 - 1 2L = 0.10
Divide by 2 to solve for L: L = 0.10 / 2 L = 0.05

Therefore, the ball costs 0.05 dollars.

A bat and ball cost 1.10 dollars total. The bat costs 1 dollar more than the ball. How much is the ball?

Answer

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