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A business sells ice cream tubs for €2 each. The probability distribution for the number of tubs sold (X) is given. Calculate the expected revenue and profit for two cost functions: CA(x) = 0.3x + 400

Mathematics

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Step 1: Define the variables and calculate the expected values of sales.
Let XX be the number of tubs sold.
The selling price per tub is €2.
The revenue function is R(x)=2xR(x) = 2x.

The probability distribution for XX is given as:
xix_i: 100, 200, 300, 400, 500
P(xi)P(x_i): 0.15, 0.20, 0.25, 0.28, 0.12

First, calculate the expected number of tubs sold, E[X]E[X]:

E[X]=∑xiP(xi)E[X] = \sum x_i P(x_i) E[X]=(100×0.15)+(200×0.20)+(300×0.25)+(400×0.28)+(500×0.12)E[X] = (100 \times 0.15) + (200 \times 0.20) + (300 \times 0.25) + (400 \times 0.28) + (500 \times 0.12) E[X]=15+40+75+112+60E[X] = 15 + 40 + 75 + 112 + 60 E[X]=302 tubsE[X] = 302 \text{ tubs}

Next, calculate the expected value of X2X^2, E[X2]E[X^2], as some cost functions depend on x2x^2:

E[X2]=∑xi2P(xi)E[X^2] = \sum x_i^2 P(x_i) E[X2]=(1002×0.15)+(2002×0.20)+(3002×0.25)+(4002×0.28)+(5002×0.12)E[X^2] = (100^2 \times 0.15) + (200^2 \times 0.20) + (300^2 \times 0.25) + (400^2 \times 0.28) + (500^2 \times 0.12) E[X2]=(10000×0.15)+(40000×0.20)+(90000×0.25)+(160000×0.28)+(250000×0.12)E[X^2] = (10000 \times 0.15) + (40000 \times 0.20) + (90000 \times 0.25) + (160000 \times 0.28) + (250000 \times 0.12) E[X2]=1500+8000+22500+44800+30000E[X^2] = 1500 + 8000 + 22500 + 44800 + 30000 E[X2]=106800E[X^2] = 106800

The expected revenue is E[R(x)]=E[2x]=2E[X]E[R(x)] = E[2x] = 2E[X]:

E[R(x)]=2×302=604 €E[R(x)] = 2 \times 302 = 604 \text{ €}

Step 2: Calculate the expected profit for each procedure.
The profit G(x)G(x) for each procedure is G(x)=R(x)−C(x)G(x) = R(x) - C(x), where C(x)C(x) is the cost function. We need to find E[G(x)]=E[R(x)]−E[C(x)]E[G(x)] = E[R(x)] - E[C(x)].

  • Procedure A: Cost function: CA(x)=0.3x+400C_A(x) = 0.3x + 400 Expected cost:

    E[CA(x)]=0.3E[X]+400E[C_A(x)] = 0.3 E[X] + 400 E[CA(x)]=(0.3×302)+400=90.6+400=490.6 €E[C_A(x)] = (0.3 \times 302) + 400 = 90.6 + 400 = 490.6 \text{ €}

    Expected profit:

    E[GA(x)]=E[R(x)]−E[CA(x)]=604−490.6=113.4 €E[G_A(x)] = E[R(x)] - E[C_A(x)] = 604 - 490.6 = 113.4 \text{ €}
  • Procedure B: Cost function: CB(x)=1x+0.04%x2=x+0.0004x2C_B(x) = 1x + 0.04\% x^2 = x + 0.0004x^2 Expected cost:

    E[CB(x)]=E[X]+0.0004E[X2]E[C_B(x)] = E[X] + 0.0004 E[X^2] E[CB(x)]=302+(0.0004×106800)=302+42.72=344.72 €E[C_B(x)] = 302 + (0.0004 \times 106800) = 302 + 42.72 = 344.72 \text{ €}

    Expected profit:

    E[GB(x)]=E[R(x)]−E[CB(x)]=604−344.72=259.28 €E[G_B(x)] = E[R(x)] - E[C_B(x)] = 604 - 344.72 = 259.28 \text{ €}
  • Procedure C: Cost function: CC(x)=0.5x+0.06%x2+150=0.5x+0.0006x2+150C_C(x) = 0.5x + 0.06\% x^2 + 150 = 0.5x + 0.0006x^2 + 150 Expected cost:

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