Step 1: Define the variables and calculate the expected values of sales.
Let X be the number of tubs sold.
The selling price per tub is €2.
The revenue function is R(x)=2x.
The probability distribution for X is given as:
xi: 100, 200, 300, 400, 500
P(xi): 0.15, 0.20, 0.25, 0.28, 0.12
First, calculate the expected number of tubs sold, E[X]:
E[X]=∑xiP(xi)
E[X]=(100×0.15)+(200×0.20)+(300×0.25)+(400×0.28)+(500×0.12)
E[X]=15+40+75+112+60
E[X]=302 tubs
Next, calculate the expected value of X2, E[X2], as some cost functions depend on x2:
E[X2]=∑xi2P(xi)
E[X2]=(1002×0.15)+(2002×0.20)+(3002×0.25)+(4002×0.28)+(5002×0.12)
E[X2]=(10000×0.15)+(40000×0.20)+(90000×0.25)+(160000×0.28)+(250000×0.12)
E[X2]=1500+8000+22500+44800+30000
E[X2]=106800
The expected revenue is E[R(x)]=E[2x]=2E[X]:
E[R(x)]=2×302=604 €
Step 2: Calculate the expected profit for each procedure.
The profit G(x) for each procedure is G(x)=R(x)−C(x), where C(x) is the cost function. We need to find E[G(x)]=E[R(x)]−E[C(x)].
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Procedure A:
Cost function: CA(x)=0.3x+400
Expected cost:
E[CA(x)]=0.3E[X]+400
E[CA(x)]=(0.3×302)+400=90.6+400=490.6 €
Expected profit:
E[GA(x)]=E[R(x)]−E[CA(x)]=604−490.6=113.4 €
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Procedure B:
Cost function: CB(x)=1x+0.04%x2=x+0.0004x2
Expected cost:
E[CB(x)]=E[X]+0.0004E[X2]
E[CB(x)]=302+(0.0004×106800)=302+42.72=344.72 €
Expected profit:
E[GB(x)]=E[R(x)]−E[CB(x)]=604−344.72=259.28 €
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Procedure C:
Cost function: CC(x)=0.5x+0.06%x2+150=0.5x+0.0006x2+150
Expected cost: