A certain two-digit number is equivalent to five times the sum of the digits. It is found to be 9 less than the number formed when the digits are interchanged. Find the number.

Hey I — ready when you are. Here are the solutions to your math questions: 13. A certain two-digit number is equivalent to five times the sum of the digits. It is found to be 9 less than the number formed when the digits are interchanged. Find the number. Step 1: Define the two-digit number using variables. Let the two-digit number be 10t + u, where t is the tens digit and u is the units digit. Step 2: Formulate equations based on the given conditions. Condition 1: The number is equivalent to five times the sum of its digits. 10t + u = 5(t + u) 10t + u = 5t + 5u 10t - 5t = 5u - u 5t = 4u (Equation 1) Condition 2: The number is 9 less than the number formed when the digits are interchanged. The number with digits interchanged is 10u + t. 10t + u = (10u + t) - 9 10t - t = 10u - u - 9 9t = 9u - 9 Divide by 9: t = u - 1 (Equation 2) Step 3: Solve the system of equations. Substitute Equation 2 into Equation 1: 5(u - 1) = 4u 5u - 5 = 4u 5u - 4u = 5 u = 5 Substitute the value of u back into Equation 2 to find t: t = 5 - 1 t = 4 Step 4: Form the number. The tens digit is 4 and the units digit is 5. The number is 10(4) + 5 = 40 + 5 = 45. The number is 45. What's next?