A child weighs 44.35 kg. Her father weighs three times as heavy as she does. a) Calculate the total weight of the child and her father. b) i) Find the HCF of 24 and 36. ii) Find the HCF of 15, 20 and

Ama's weight = 44.35 kg.

The father weighs three times as heavy as Ama.
Father's weight = $3 \times 44.35$ kg.

Total weight = Ama's weight + Father's weight
Total weight = $44.35 \text{ kg} + 133.05 \text{ kg}$

The total weight of Ama and her father is $\boxed{177.40 \text{ kg}}$.

b) i)

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24.

Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36.

Common factors: 1, 2, 3, 4, 6, 12.

The highest common factor is the largest number in the list of common factors.
HCF(24, 36) = 12.

The HCF of 24 and 36 is $\boxed{12}$.

b) ii)

Factors of 15: 1, 3, 5, 15.

Factors of 20: 1, 2, 4, 5, 10, 20.

Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30.

Common factors: 1, 5.

The highest common factor is the largest number in the list of common factors.
HCF(15, 20, 30) = 5.

The HCF of 15, 20 and 30 is $\boxed{5}$.

c)

Given values: 0.125, $\frac{1}{4}$, 0.12.
Convert $\frac{1}{4}$ to a decimal:

The values in decimal form are: 0.125, 0.25, 0.12.

Comparing 0.125, 0.250, and 0.120:
0.120 is the smallest.
0.125 is the next smallest.
0.250 is the largest.

The values in ascending order are $\boxed{0.12, 0.125, \frac{1}{4}}$.