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A father is 3 times as old as his son. After 12 years, his age will be twice as that of his son then. Find their present ages.

Mathematics

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1. A father is 3 times as old as his son. After 12 years, his age will be twice as that of his son then. Find their present ages.

  1. Define variables for their present ages.

    Let the father's present age be FF years.
    Let the son's present age be SS years.

  2. Formulate equations based on the given information.

    From the first statement: "A father is 3 times as old as his son."

    F=3S(∗)F = 3S \quad (*)

    After 12 years:
    Father's age will be F+12F+12.
    Son's age will be S+12S+12.

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