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A circle of area 9cm² and radius 9cm is mapped onto a sector of area 16cm² and diameter 16cm. Calculate the value of θ.

Mathematics

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Answer

8π cm\frac{8}{\sqrt{\pi}} \text{ cm}

Step-by-step solution

3 steps
  1. Tafuta eneo la duara la kwanza.

    Radiasi ya duara la kwanza, r1=9 cmr_1 = 9 \text{ cm}.
    Eneo la duara la kwanza, A1A_1, linahesabiwa kwa kutumia fomula A=πr2A = \pi r^2.

    A1=π(9 cm)2A_1 = \pi (9 \text{ cm})^2 A1=81π cm2A_1 = 81\pi \text{ cm}^2
  2. Tafuta radiasi ya duara la pili.

    Eneo la duara la pili, A2A_2, limepewa kama 16 cm216 \text{ cm}^2.
    Acha r2r_2 iwe radiasi ya duara la pili. Tunajua A2=πr22A_2 = \pi r_2^2.

    16 cm2=πr2216 \text{ cm}^2 = \pi r_2^2

    Ili kupata r22r_2^2, tunagawanya pande zote mbili kwa π\pi:

    r22=16π cm2r_2^2 = \frac{16}{\pi} \text{ cm}^2

    Ili kupata r2r_2, tunachukua mzizi wa mraba wa pande zote mbili:

    r2=16π cmr_2 = \sqrt{\frac{16}{\pi}} \text{ cm} r2=4π cmr_2 = \frac{4}{\sqrt{\pi}} \text{ cm}
  3. Kokotoa thamani ya dd (kipenyo cha duara la pili).

    Kipenyo dd ni mara mbili ya radiasi r2r_2.

    d=2r2d = 2 r_2 d=2×4π cmd = 2 \times \frac{4}{\sqrt{\pi}} \text{ cm} d=8π cmd = \frac{8}{\sqrt{\pi}} \text{ cm}

    Thamani ya dd ni:

    8π cm\boxed{\frac{8}{\sqrt{\pi}} \text{ cm}}

    Hili ndilo la mwisho la bure leo — litumie vizuri kesho, au andika /upgrade kwa maswali yasiyo na kikomo.

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