A committee of 6 people is to be chosen from 7 mid-fielders (M), 5 attackers (A), and 8 referees (R). a) exactly one attacker and one mid-fielder?

Here are the solutions to the problems. --- Question 9: A committee of 6 people is to be chosen from 7 mid-fielders (M), 5 attackers (A), and 8 referees (R). a) exactly one attacker and one mid-fielder; Step 1: Calculate the number of ways to choose 1 attacker and 1 mid-fielder. Number of ways to choose 1 attacker from 5: 51 = 5. Number of ways to choose 1 mid-fielder from 7: 71 = 7. **Step 2: Calculate the number of ways

A committee of 6 people is to be chosen from 7 mid-fielders (M), 5 attackers (A), and 8 referees (R). a) exactly one attacker and one mid-fielder?

Here are the solutions to the problems. --- Question 9: A committee of 6 people is to be chosen from 7 mid-fielders (M), 5 attackers (A), and 8 referees (R). a) exactly one attacker and one mid-fielder; Step 1: Calculate the number of ways to choose 1 attacker and 1 mid-fielder. Number of ways to choose 1 attacker from 5: 51 = 5. Number of ways to choose 1 mid-fielder from 7: 71 = 7. **Step 2: Calculate the number of ways

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Here are the solutions to the problems.

Part 9

A committee of 6 people is to be chosen from 7 mid-fielders (M), 5 attackers (A), and 8 referees (R).

Part a· 2 steps

exactly one attacker and one mid-fielder;

Calculate the number of ways to choose 1 attacker and 1 mid-fielder.
Number of ways to choose 1 attacker from 5: $\binom{5}{1} = 5$ .
Number of ways to choose 1 mid-fielder from 7: $\binom{7}{1} = 7$ .
Calculate the number of ways

A committee of 6 people is to be chosen from 7 mid-fielders (M), 5 attackers (A), and 8 referees (R). a) exactly one attacker and one mid-fielder?

Step-by-step solution

Part 9

Part a· 2 steps

Calculate the number of ways to choose 1 attacker and 1 mid-fielder.

Calculate the number of ways

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