A research team has 8 software engineers, 6 analysts, and 4 programmers. A committee of 4 members is to be selected. Find the number of ways to select the committee if: i) all members are software eng

The number of committees consisting of all Software engineers is $\boxed{\text{70}}$.

Choose 2 analysts from 6: $C(6, 2) = \frac{6 \times 5}{2 \times 1} = 15$.
Choose 2 non-analysts from 12: $C(12, 2) = \frac{12 \times 11}{2 \times 1} = 66$.
Number of ways = $15 \times 66 = 990$.

Choose 3 analysts from 6: $C(6, 3) = \frac{6 \times 5 \times 4}{3 \times 2 \times 1} = 20$.
Choose 1 non-analyst from 12: $C(12, 1) = 12$.
Number of ways = $20 \times 12 = 240$.

Choose 4 analysts from 6: $C(6, 4) = \frac{6 \times 5 \times 4 \times 3}{4 \times 3 \times 2 \times 1} = 15$.
Choose 0 non-analysts from 12: $C(12, 0) = 1$.
Number of ways = $15 \times 1 = 15$.

Total ways = $990 + 240 + 15 = 1245$.
The number of committees with at least two analysts is $\boxed{\text{1245}}$.

Choose 0 programmers from 4: $C(4, 0) = 1$.
Choose 4 non-programmers from 14: $C(14, 4) = \frac{14 \times 13 \times 12 \times 11}{4 \times 3 \times 2 \times 1} = 1001$.
Number of ways = $1 \times 1001 = 1001$.

Choose 1 programmer from 4: $C(4, 1) = 4$.
Choose 3 non-programmers from 14: $C(14, 3) = \frac{14 \times 13 \times 12}{3 \times 2 \times 1} = 364$.
Number of ways = $4 \times 364 = 1456$.

Total ways = $1001 + 1456 = 2457$.
The number of committees with at most one programmer is $\boxed{\text{2457}}$.