A committee of 6 people is to be chosen from 7 mid-fielders (M), 5 attackers (A), and 8 referees (R). a) exactly one attacker and one mid-fielder.

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Asked on May 21, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

Accepted Answer · 2026-05-21T08:53:27.692Z

Welcome back ♡tasha♡....🧸 — missed you this week. Here are the solutions to the problems. --- Question 9: A committee of 6 people is to be chosen from 7 mid-fielders (M), 5 attackers (A), and 8 referees (R). Total available: M=7, A=5, R=8. Committee size = 6. a) exactly one attacker and one mid-fielder; Step 1: Select 1 attacker, 1 mid-fielder, and the remaining 4 from referees. The number of ways to choose 1 attacker from 5 is 51. The number of ways to choose 1 mid-fielder from

Accepted Answer · 2026-05-21T08:53:27.692Z

Welcome back ♡tasha♡....🧸 — missed you this week. Here are the solutions to the problems. --- Question 9: A committee of 6 people is to be chosen from 7 mid-fielders (M), 5 attackers (A), and 8 referees (R). Total available: M=7, A=5, R=8. Committee size = 6. a) exactly one attacker and one mid-fielder; Step 1: Select 1 attacker, 1 mid-fielder, and the remaining 4 from referees. The number of ways to choose 1 attacker from 5 is 51. The number of ways to choose 1 mid-fielder from

A committee of 6 people is to be chosen from 7 mid-fielders (M), 5 attackers (A), and 8 referees (R). a) exactly one attacker and one mid-fielder.

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A committee of 6 people is to be chosen from 7 mid-fielders (M), 5 attackers (A), and 8 referees (R). a) exactly one attacker and one mid-fielder.

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