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A cyclist travels from point A to point B, a distance of 12 km, in 30 minutes. They then stop at point B for 1.5 hours before cycling to point C, 20 km from A, in another 30 minutes. Draw a distance-t

Mathematics

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a) To draw the distance-time graph for the cyclist:

Step 1: Determine the coordinates for each segment of the journey.

  • Segment 1: From A to B

    • Start time: 6:30 am
    • End time: 7:00 am
    • Duration: 7:00 am−6:30 am=30 minutes7:00 \text{ am} - 6:30 \text{ am} = 30 \text{ minutes}
    • Distance covered: 12 km
    • Point 1: (6:30 am,0 km)(6:30 \text{ am}, 0 \text{ km})
    • Point 2: (7:00 am,12 km)(7:00 \text{ am}, 12 \text{ km})
  • Segment 2: Stop at B

    • Start time: 7:00 am
    • Duration of stop: 112 hours=1 hour 30 minutes1\frac{1}{2} \text{ hours} = 1 \text{ hour } 30 \text{ minutes}
    • End time of stop: 7:00 am+1 hour 30 minutes=8:30 am7:00 \text{ am} + 1 \text{ hour } 30 \text{ minutes} = 8:30 \text{ am}
    • Distance covered: 0 km (distance remains 12 km)
    • Point 3: (8:30 am,12 km)(8:30 \text{ am}, 12 \text{ km})
  • Segment 3: From B to C

    • Start time: 8:30 am
    • Starting distance: 12 km
    • Destination C is 20 km away.
    • Distance to cover: 20 km−12 km=8 km20 \text{ km} - 12 \text{ km} = 8 \text{ km}
    • Speed: 16 km/h
    • Time taken: Time=DistanceSpeed=8 km16 km/h=0.5 hours=30 minutes\text{Time} = \frac{\text{Distance}}{\text{Speed}} = \frac{8 \text{ km}}{16 \text{ km/h}} = 0.5 \text{ hours} = 30 \text{ minutes}
    • End time: 8:30 am+30 minutes=9:00 am8:30 \text{ am} + 30 \text{ minutes} = 9:00 \text{ am}
    • End distance: 20 km
    • Point 4: (9:00 am,20 km)(9:00 \text{ am}, 20 \text{ km})

Step 2: Set up the graph axes according to the given scale.

  • Vertical axis (Distance): 2 cm represents 4 km. If each grid square is 1 cm, then 2 squares represent 4 km. Label the axis from 0 km to 20 km (e.g., 0, 4, 8, 12, 16, 20).
  • Horizontal axis (Time): 2 cm represents 30 minutes. If each grid square is 1 cm, then 2 squares represent 30 minutes. Label the axis starting from 6:30 am (e.g., 6:30 am, 7:00 am, 7:30 am, 8:00 am, 8:30 am, 9:00 am).

Step 3: Plot the points and draw the graph.

  1. Plot the starting point: (6:30 am,0 km)(6:30 \text{ am}, 0 \text{ km}).
  2. Draw a straight line from (6:30 am,0 km)(6:30 \text{ am}, 0 \text{ km}) to (7:00 am,12 km)(7:00 \text{ am}, 12 \text{ km}).
  3. Draw a horizontal line from (7:00 am,12 km)(7:00 \text{ am}, 12 \text{ km}) to (8:30 am,12 km)(8:30 \text{ am}, 12 \text{ km}) to represent the stop.
  4. Draw a straight line from (8:30 am,12 km)(8:30 \text{ am}, 12 \text{ km}) to (9:00 am,20 km)(9:00 \text{ am}, 20 \text{ km}).

b) To find the time taken for the cyclist to reach the destination using the graph:

Step 1: Locate the destination distance on the vertical axis.
The destination is 20 km. Find 20 km on the vertical axis.

Step 2: Read the corresponding time on the horizontal axis.
Follow horizontally from 20 km to the graph line, then vertically down to the time axis. This point corresponds to 9:00 am.

Step 3: Calculate the total time taken.
The journey started at 6:30 am and ended at 9:00 am.

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