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It is given that p = 3.6 x 104 and q = 9 x 10⁻⁴. Find, giving the answers in standard form: a) pq b) p/q. 2) m = 2 x 103 and n = 5 x 10. Find: a) mn b) n/m.

Mathematics

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here are the solutions for the standard form problems.

1) Given p=3.6×104p = 3.6 \times 10^4 and q=9×104q = 9 \times 10^4.

a) Find pqpq

  1. Multiply the numerical parts and the powers of 10 separately.

    pq=(3.6×104)×(9×104)pq = (3.6 \times 10^4) \times (9 \times 10^4) pq=(3.6×9)×(104×104)pq = (3.6 \times 9) \times (10^4 \times 10^4)
  2. Perform the multiplication and apply the exponent rule am×an=am+na^m \times a^n = a^{m+n}.

    pq=32.4×104+4pq = 32.4 \times 10^{4+4} pq=32.4×108pq = 32.4 \times 10^8
  3. Convert the result to standard form (a number between 1 and 10 multiplied by a power of 10).

    32.4=3.24×10132.4 = 3.24 \times 10^1 pq=(3.24×101)×108pq = (3.24 \times 10^1) \times 10^8 pq=3.24×101+8pq = 3.24 \times 10^{1+8} pq=3.24×109pq = \boxed{3.24 \times 10^9}

    b) Find pq\frac{p}{q}

  4. Divide the numerical parts and the powers of 10 separately.

    pq=3.6×1049×104\frac{p}{q} = \frac{3.6 \times 10^4}{9 \times 10^4} pq=(3.69)×(104104)\frac{p}{q} = \left(\frac{3.6}{9}\right) \times \left(\frac{10^4}{10^4}\right)
  5. Perform the division and apply the exponent rule aman=am−n\frac{a^m}{a^n} = a^{m-n}.

    pq=0.4×104−4\frac{p}{q} = 0.4 \times 10^{4-4} pq=0.4×100\frac{p}{q} = 0.4 \times 10^0 pq=0.4×1\frac{p}{q} = 0.4 \times 1 pq=0.4\frac{p}{q} = 0.4
  6. Convert the result to standard form.

    0.4=4×10−10.4 = 4 \times 10^{-1} pq=4×10−1\frac{p}{q} = \boxed{4 \times 10^{-1}}

    2) Given m=2×103m = 2 \times 10^3 and n=5×10n = 5 \times 10.
    Note that n=5×101n = 5 \times 10^1.

    a) Find mnmn

  7. Multiply the numerical parts and the powers of 10 separately.

    mn=(2×103)×(5×101)mn = (2 \times 10^3) \times (5 \times 10^1) mn=(2×5)×(103×101)mn = (2 \times 5) \times (10^3 \times 10^1)
  8. Perform the multiplication and apply the exponent rule am×an=am+na^m \times a^n = a^{m+n}.

    mn=10×103+1mn = 10 \times 10^{3+1} mn=10×104mn = 10 \times 10^4
  9. Convert the result to standard form.

    10=1×10110 = 1 \times 10^1 mn=(1×101)×104mn = (1 \times 10^1) \times 10^4 mn=1×101+4mn = 1 \times 10^{1+4} mn=1×105mn = \boxed{1 \times 10^5}

    b) Find nm\frac{n}{m}

  10. Divide the numerical parts and the powers of 10 separately.

    nm=5×1012×103\frac{n}{m} = \frac{5 \times 10^1}{2 \times 10^3} nm=(52)×(101103)\frac{n}{m} = \left(\frac{5}{2}\right) \times \left(\frac{10^1}{10^3}\right)
  11. Perform the division and apply the exponent rule aman=am−n\frac{a^m}{a^n} = a^{m-n}.

    nm=2.5×101−3\frac{n}{m} = 2.5 \times 10^{1-3} nm=2.5×10−2\frac{n}{m} = 2.5 \times 10^{-2}

    This result is already in standard form.

    nm=2.5×10−2\frac{n}{m} = \boxed{2.5 \times 10^{-2}}
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