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A drum can hold 200 l of water. Calculate the volume of water in the drum when it is: 6.1 2/5 full, 6.2 half full, 6.3 13/20 full.

Mathematics

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3 parts
6.1

80 L\text{80 L}

6.2

100 L\text{100 L}

6.3

130 L\text{130 L}

Step-by-step solution

6 steps

Here's the solution for question 6:

Part 6.1· 2 steps

  1. Identify the total capacity and the fraction of the drum that is full.

    Total capacity =200 L= 200\, \text{L}
    Fraction full =25= \frac{2}{5}

  2. Calculate the volume of water.

    Volume=200 L×25\text{Volume} = 200\, \text{L} \times \frac{2}{5} Volume=4005 L\text{Volume} = \frac{400}{5}\, \text{L} Volume=80 L\text{Volume} = 80\, \text{L}

    The volume of water is 80 L\boxed{\text{80 L}}.

Part 6.2

100 L\text{100 L}

  1. Identify the total capacity and the fraction of the drum that is full.

    Total capacity =200 L= 200\, \text{L}
    Fraction full =half=12= \text{half} = \frac{1}{2}

  2. Calculate the volume of water.

    Volume=200 L×12\text{Volume} = 200\, \text{L} \times \frac{1}{2} Volume=2002 L\text{Volume} = \frac{200}{2}\, \text{L} Volume=100 L\text{Volume} = 100\, \text{L}

    The volume of water is 100 L\boxed{\text{100 L}}.

Part 6.3

130 L\text{130 L}

  1. Identify the total capacity and the fraction of the drum that is full.

    Total capacity =200 L= 200\, \text{L}
    Fraction full =1320= \frac{13}{20}

  2. Calculate the volume of water.

    Volume=200 L×1320\text{Volume} = 200\, \text{L} \times \frac{13}{20} Volume=200×1320 L\text{Volume} = \frac{200 \times 13}{20}\, \text{L} Volume=10×13 L\text{Volume} = 10 \times 13\, \text{L} Volume=130 L\text{Volume} = 130\, \text{L}

    The volume of water is 130 L\boxed{\text{130 L}}.

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