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A factory manufactures 518 bulbs everyday. How many bulbs did it manufacture in the month of December?

Mathematics

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20. There are 215 members in a society. Every member deposits ₹ 521 as membership fee. How many rupees in all are collected as membership fee?

  • Step 1: Identify the given values. Number of members = 215 Membership fee per member = ₹ 521
  • Step 2: Calculate the total amount collected. Total amount = Number of members ×\times Membership fee per member Total amount = 215×521215 \times 521 Total amount = 112015

The total amount collected as membership fee is ₹ 112015.

21. A factory manufactures 518 bulbs everyday. How many bulbs did it manufacture in the month of December?

  • Step 1: Identify the given values and number of days. Bulbs manufactured per day = 518 Number of days in December = 31
  • Step 2: Calculate the total bulbs manufactured in December. Total bulbs = Bulbs per day ×\times Number of days Total bulbs = 518×31518 \times 31 Total bulbs = 16058

The factory manufactured 16058 bulbs in December.

22. 7429 books are to be arranged on 17 shelves. If the number of books placed on each shelf is the same, how many books will be placed on each shelf?

  • Step 1: Identify the given values. Total number of books = 7429 Number of shelves = 17
  • Step 2: Calculate the number of books per shelf. Books per shelf = Total books ÷\div Number of shelves Books per shelf = 7429÷177429 \div 17 Books per shelf = 437

There will be 437 books placed on each shelf.

23. 816 students of a school go on picnic by buses. Each bus carries 48 students. How many buses are used to carry the students on picnic?

  • Step 1: Identify the given values. Total number of students = 816 Capacity of each bus = 48 students
  • Step 2: Calculate the number of buses needed. Number of buses = Total students ÷\div Capacity per bus Number of buses = 816÷48816 \div 48 Number of buses = 17

17 buses are used to carry the students on the picnic.

24. There are 1887 trees in 17 rows in a garden. If the number of trees is the same in each row, how many trees are there in one row?

  • Step 1: Identify the given values. Total number of trees = 1887 Number of rows = 17
  • Step 2: Calculate the number of trees per row. Trees per row = Total trees ÷\div Number of rows Trees per row = 1887÷171887 \div 17 Trees per row = 111

There are 111 trees in one row.

25. The cost of 15 copies is ₹ 210. What is the cost of one dozen copies?

  • Step 1: Find the cost of one copy. Cost of 1 copy = Total cost ÷\div Number of copies Cost of 1 copy = 210÷15210 \div 15 Cost of 1 copy = ₹ 14
  • Step 2: Calculate the cost of one dozen copies. One dozen = 12 copies Cost of 12 copies = Cost of 1 copy ×\times 12 Cost of 12 copies = 14×1214 \times 12 Cost of 12 copies = ₹ 168

The cost of one dozen copies is ₹ 168.

26. There are 12 dozen bottles in 6 crates. How many bottles will be in 8 crates?

  • Step 1: Calculate the total number of bottles in 6 crates. 1 dozen = 12 bottles Total bottles in 6 crates = 12 dozen ×\times 12 bottles/dozen Total bottles in 6 crates = 12×12=14412 \times 12 = 144 bottles
  • Step 2: Find the number of bottles per crate. Bottles per crate = Total bottles ÷\div Number of crates Bottles per crate = 144÷6144 \div 6 Bottles per crate = 24 bottles
  • Step 3: Calculate the number of bottles in 8 crates. Bottles in 8 crates = Bottles per crate ×\times 8 Bottles in 8 crates = 24×824 \times 8 Bottles in 8 crates = 192 bottles

There will be 192 bottles in 8 crates.

27. A car consumes 5 litres of petrol in running 95 kilometres. How many kilometres will it run if it consumes 12 litres?

  • Step 1: Find the distance covered per litre of petrol. Distance per litre = Total distance ÷\div Litres consumed Distance per litre = 95÷595 \div 5 Distance per litre = 19 km/litre
  • Step 2: Calculate the distance covered with 12 litres. Distance with 12 litres = Distance per litre ×\times 12 Distance with 12 litres = 19×1219 \times 12 Distance with 12 litres = 228 km

The car will run 228 kilometres if it consumes 12 litres of petrol.

28. Write first four multiples of:

  • i. 5: 5×1=55 \times 1 = 5 5×2=105 \times 2 = 10 5×3=155 \times 3 = 15 5×4=205 \times 4 = 20 The first four multiples of 5 are 5, 10, 15, 20\boxed{\text{5, 10, 15, 20}}.

  • ii. 6: 6×1=66 \times 1 = 6 6×2=126 \times 2 = 12 6×3=186 \times 3 = 18 6×4=246 \times 4 = 24 The first four multiples of 6 are 6, 12, 18, 24\boxed{\text{6, 12, 18, 24}}.

  • iii. 4: 4×1=44 \times 1 = 4 4×2=84 \times 2 = 8 4×3=124 \times 3 = 12 4×4=164 \times 4 = 16 The first four multiples of 4 are 4, 8, 12, 16\boxed{\text{4, 8, 12, 16}}.

  • iv. 3: 3×1=33 \times 1 = 3 3×2=63 \times 2 = 6 3×3=93 \times 3 = 9 3×4=123 \times 4 = 12 The first four multiples of 3 are 3, 6, 9, 12\boxed{\text{3, 6, 9, 12}}.

  • v. 10: 10×1=1010 \times 1 = 10 10×2=2010 \times 2 = 20 10×3=3010 \times 3 = 30 10×4=4010 \times 4 = 40 The first four multiples of 10 are 10, 20, 30, 40\boxed{\text{10, 20, 30, 40}}.

  • vi. 12: 12×1=1212 \times 1 = 12 12×2=2412 \times 2 = 24 12×3=3612 \times 3 = 36 12×4=4812 \times 4 = 48 The first four multiples of 12 are 12, 24, 36, 48\boxed{\text{12, 24, 36, 48}}.

29. Write all the factors of:

  • i. 8: Factors of 8 are numbers that divide 8 evenly. 1×8=81 \times 8 = 8 2×4=82 \times 4 = 8 The factors of 8 are 1, 2, 4, 8\boxed{\text{1, 2, 4, 8}}.

  • ii. 12: Factors of 12 are numbers that divide 12 evenly. 1×12=121 \times 12 = 12 2×6=122 \times 6 = 12 3×4=123 \times 4 = 12 The factors of 12 are 1, 2, 3, 4, 6, 12\boxed{\text{1, 2, 3, 4, 6, 12}}.

  • iii. 36: Factors of 36 are numbers that divide 36 evenly. 1×36=361 \times 36 = 36 2×18=362 \times 18 = 36 3×12=363 \times 12 = 36 4×9=364 \times 9 = 36 6×6=366 \times 6 = 36 The factors of 36 are $\boxed{\text{1, 2, 3, 4, 6, 9, 1

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