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A farmer has three oxen. One ox ploughs an acre of land in x hours, the other ox ploughs the same acre of land in y hours and the third ox uses 12 hours to plough the same piece of land. If three oxen are used at the same time, it takes 4 hours to plough the acre of land, find the value of y.

Mathematics

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Answer

18

Step-by-step solution

5 steps

Hili ni tatizo la viwango vya kazi. Kwanza, tutaamua kiwango cha kazi cha kila ng'ombe kwa saa, kisha tutatumia kiwango cha jumla cha kazi wanapofanya kazi pamoja.

  1. Andika viwango vya kazi vya kila ng'ombe.

    Kiwango cha kazi ni kiasi cha kazi kinachofanywa kwa kila kitengo cha muda. Katika kesi hii, kazi ni kulima ekari 1 ya ardhi.

    • Ng'ombe wa kwanza hulima ekari 1 kwa saa 9. Kiwango chake ni 19\frac{1}{9} ya ekari kwa saa.
    • Ng'ombe wa pili hulima ekari 1 kwa saa yy. Kiwango chake ni 1y\frac{1}{y} ya ekari kwa saa.
    • Ng'ombe wa tatu hulima ekari 1 kwa saa 12. Kiwango chake ni 112\frac{1}{12} ya ekari kwa saa.
    • Ng'ombe wote watatu wakifanya kazi pamoja, hulima ekari 1 kwa saa 4. Kiwango chao cha jumla ni 14\frac{1}{4} ya ekari kwa saa.
  2. Unda mlinganyo kwa kujumlisha viwango vya kazi vya ng'ombe binafsi na kuvilinganisha na kiwango cha jumla.

    19+1y+112=14\frac{1}{9} + \frac{1}{y} + \frac{1}{12} = \frac{1}{4}
  3. Tenga neno lenye yy upande mmoja wa mlinganyo.

    Ili kufanya hivyo, toa 19\frac{1}{9} na 112\frac{1}{12} kutoka pande zote mbili za mlinganyo.

    1y=14−19−112\frac{1}{y} = \frac{1}{4} - \frac{1}{9} - \frac{1}{12}
  4. Tafuta kigawo cha kawaida kidogo (LCM) cha 4, 9, na 12, ambacho ni 36.

    Kisha, rahisiisha mlinganyo.

    1y=936−436−336\frac{1}{y} = \frac{9}{36} - \frac{4}{36} - \frac{3}{36} 1y=9−4−336\frac{1}{y} = \frac{9 - 4 - 3}{36} 1y=236\frac{1}{y} = \frac{2}{36} 1y=118\frac{1}{y} = \frac{1}{18}
  5. Tatua kwa yy.

    Kwa kuwa 1y=118\frac{1}{y} = \frac{1}{18}, basi yy lazima iwe 18.

    y=18y = 18

    Thamani ya yy ni 18 saa.

    The value of yy is:

    1818
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