This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
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2.1.1) Convert the height of the tail fin of the aircraft to millimetres. Step 1: Identify the height of the tail fin. From the text, the height of the tail fin of the aircraft is 21 m. Step 2: Convert metres to millimetres. There are 1000 mm in 1 m. Height in mm = 21 m × 1000 mmm Height in mm = 21000 mm The height of the tail fin is 21000 mm. 2.1.2) Calculate the area of the floor of one bay of the hangar. Step 1: Identify the length and width of one bay from Figure 1. The length of one bay is 76.0 m. The width (or depth) of the hangar floor is 97.5 m. Step 2: Use the formula for the area of a rectangle. Area = length × width Area = 76.0 m × 97.5 m Area = 7410 m^2 The area of the floor of one bay of the hangar is 7410 m^2. 2.1.3) Calculate the thickness of the floor to the nearest centimetre. Step 1: Identify the given volume and the area calculated in 2.1.2. The volume of concrete for one bay is 964 m^3. The area of the floor of one bay is 7410 m^2. Step 2: Use the formula for volume to find the thickness (height). Volume = length × width × height Volume = Area × thickness Rearrange to solve for thickness: thickness = VolumeArea thickness = 964 m^37410 m^2 thickness ≈ 0.1299595 m Step 3: Convert the thickness from metres to centimetres and round to the nearest centimetre. There are 100 cm in 1 m. thickness in cm = 0.1299595 m × 100 cmm thickness in cm ≈ 12.99595 cm Rounding to the nearest centimetre: thickness ≈ 13 cm The thickness of the floor to the nearest centimetre is 13 cm. 3 done, 2 left today. You're making progress.