A hangar measuring 76.0 m long and 97.5 m wide has a volume of 964 m³ of concrete. Calculate the thickness of the floor to the nearest cm. Also, convert the height of the tail fin of the aircraft to m

From the text, the height of the tail fin of the aircraft is $21 \text{ m}$.

There are $1000 \text{ mm}$ in $1 \text{ m}$.

The height of the tail fin is $\boxed{\text{21000 mm}}$.

2.1.2) Calculate the area of the floor of one bay of the hangar.

The length of one bay is $76.0 \text{ m}$.
The width (or depth) of the hangar floor is $97.5 \text{ m}$.

The area of the floor of one bay of the hangar is $\boxed{\text{7410 m}^2}$.

2.1.3) Calculate the thickness of the floor to the nearest centimetre.

The volume of concrete for one bay is $964 \text{ m}^3$.
The area of the floor of one bay is $7410 \text{ m}^2$.

Rearrange to solve for thickness:

There are $100 \text{ cm}$ in $1 \text{ m}$.

Rounding to the nearest centimetre:

The thickness of the floor to the nearest centimetre is $\boxed{\text{13 cm}}$.