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A hard disk of 4gb is required to store a pile of 800mb and another pile of 2.4gb. What capacity of the hard disk is free? (b) What is the total pile stored in mb.

Mathematics

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Answer

838.4 MB or 0.81875 GB\text{838.4 MB or 0.81875 GB}

3257.6 MB\text{3257.6 MB}

Step-by-step solution

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Here are the solutions to your assignment problems:

Problem A: A hard disk of 4 GB4 \text{ GB} is required to store a pile of 800 MB800 \text{ MB} and another pile of 2.4 GB2.4 \text{ GB}. What capacity of the hard disk is free?

  1. Convert all capacities to a common unit, Megabytes (MB\text{MB}), using the conversion 1 GB=1024 MB1 \text{ GB} = 1024 \text{ MB}.

    Hard disk capacity:

    4 GB=4×1024 MB=4096 MB4 \text{ GB} = 4 \times 1024 \text{ MB} = 4096 \text{ MB}

    First file size: 800 MB800 \text{ MB}
    Second file size:

    2.4 GB=2.4×1024 MB=2457.6 MB2.4 \text{ GB} = 2.4 \times 1024 \text{ MB} = 2457.6 \text{ MB}
  2. Calculate the total space used by the files.

    Total used space=800 MB+2457.6 MB=3257.6 MB\text{Total used space} = 800 \text{ MB} + 2457.6 \text{ MB} = 3257.6 \text{ MB}
  3. Calculate the free capacity on the hard disk.

    Free capacity=Total hard disk capacity−Total used space\text{Free capacity} = \text{Total hard disk capacity} - \text{Total used space} Free capacity=4096 MB−3257.6 MB=838.4 MB\text{Free capacity} = 4096 \text{ MB} - 3257.6 \text{ MB} = 838.4 \text{ MB}

    To express this in Gigabytes (GB\text{GB}):

    Free capacity=838.41024 GB=0.81875 GB\text{Free capacity} = \frac{838.4}{1024} \text{ GB} = 0.81875 \text{ GB}

    The free capacity of the hard disk is 838.4 MB or 0.81875 GB\boxed{\text{838.4 MB or 0.81875 GB}}.

    Problem B: What is the total pile stored in MB\text{MB}?

  4. Use the file sizes already converted to MB\text{MB} from Problem A.

    First file size: 800 MB800 \text{ MB}
    Second file size: 2.4 GB=2457.6 MB2.4 \text{ GB} = 2457.6 \text{ MB}

  5. Calculate the total stored capacity in MB\text{MB}.

    Total stored capacity=800 MB+2457.6 MB=3257.6 MB\text{Total stored capacity} = 800 \text{ MB} + 2457.6 \text{ MB} = 3257.6 \text{ MB}

    The total pile stored is 3257.6 MB\boxed{\text{3257.6 MB}}.

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