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A) i) Calculate angle CDE. ii) Calculate length of CD.

Mathematics

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here's the solution to question 23:

Part a(i)· 3 steps

Calculate ∠CDE\angle CDE

  1. Identify properties of the tangent.

    The radius OC is perpendicular to the tangent EC at the point of contact C.
    Therefore, ∠OCE=90∘\angle OCE = 90^\circ.

  2. Calculate ∠OCD\angle OCD.

    Given ∠ECD=45∘\angle ECD = 45^\circ.

    ∠OCD=∠OCE−∠ECD=90∘−45∘=45∘\angle OCD = \angle OCE - \angle ECD = 90^\circ - 45^\circ = 45^\circ
  3. Use properties of isosceles triangle △OCD\triangle OCD.

    Since O is the center, OC and OD are radii, so OC=ODOC = OD.
    Therefore

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