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A) If Ksh. 1 = 0.007524, how many Kenyan shillings make 1? b) X c) The scale of a map is 1cm: 52500m. How many cm on the map represent 1m on the ground? d) Machine A can complete a task in 8 hours, Ma

Mathematics

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Step-by-step solution

4 steps
  1. Solve part a).

    Given that Ksh. 1 is equal to 0.007524 US Dollars. To find how many Kenyan shillings make 1 US dollar, we need to find the reciprocal of the given rate.

    1 US dollar=10.007524 Ksh1 \text{ US dollar} = \frac{1}{0.007524} \text{ Ksh} 1 US dollar≈132.9079 Ksh1 \text{ US dollar} \approx 132.9079 \text{ Ksh}

    Rounding to two decimal places:

    1 US dollar≈132.91 Ksh1 \text{ US dollar} \approx 132.91 \text{ Ksh}

    Therefore, 132.91 Kenyan shillings\boxed{132.91 \text{ Kenyan shillings}} make 1 US dollar.

  2. Part b) is missing from the provided image.

  3. Solve part c) (scale conversion).

    Given that 1 cm on the drawing represents 52500 m on the ground. We need to find how many cm are equivalent to 1 m.
    The scale is:

    1 cm≡52500 m1 \text{ cm} \equiv 52500 \text{ m}

    To find the equivalent of 1 m in cm, divide both sides by 52500:

    152500 cm≡5250052500 m\frac{1}{52500} \text{ cm} \equiv \frac{52500}{52500} \text{ m} 152500 cm≡1 m\frac{1}{52500} \text{ cm} \equiv 1 \text{ m}

    As a decimal:

    152500≈0.0000190476 cm\frac{1}{52500} \approx 0.0000190476 \text{ cm}

    Rounding to a reasonable number of significant figures, or leaving as a fraction:

    1 m≡152500 cm1 \text{ m} \equiv \boxed{\frac{1}{52500} \text{ cm}}
  4. Solve part d) (work rate problem, labeled as (c) in the question).

    Let the total task be 1 unit of work.

    • Machine A takes 8 hours, so its work rate (RAR_A) is 18\frac{1}{8} task/hour.
    • Machine B takes 10 hours, so its work rate (RBR_B) is 110\frac{1}{10} task/hour.
    • Machine A and C working together take 5 hours, so their combined work rate (RA+CR_{A+C}) is 15\frac{1}{5} task/hour.

    First, find the work rate of Machine C (RCR_C):

    RA+C=RA+RCR_{A+C} = R_A + R_C 15=18+RC\frac{1}{5} = \frac{1}{8} + R_C RC=15−18R_C = \frac{1}{5} - \frac{1}{8}

    To subtract, find a common denominator, which is 40:

    RC=840−540R_C = \frac{8}{40} - \frac{5}{40} RC=340 task/hourR_C = \frac{3}{40} \text{ task/hour}

    Next, find the combined work rate of Machine B and Machine C (RB+CR_{B+C}):

    RB+C=RB+RCR_{B+C} = R_B + R_C RB+C=110+340R_{B+C} = \frac{1}{10} + \frac{3}{40}

    To add, find a common denominator, which is 40:

    RB+C=440+340R_{B+C} = \frac{4}{40} + \frac{3}{40} RB+C=740 task/hourR_{B+C} = \frac{7}{40} \text{ task/hour}

    Finally, determine the time it would take Machine B and Machine C working together (TB+CT_{B+C}):

    TB+C=1RB+CT_{B+C} = \frac{1}{R_{B+C}} TB+C=1740T_{B+C} = \frac{1}{\frac{7}{40}} TB+C=407 hoursT_{B+C} = \frac{40}{7} \text{ hours}

    As a mixed number:

    TB+C=557 hoursT_{B+C} = 5 \frac{5}{7} \text{ hours}

    The time it would take Machine B and Machine C working together is 407 hours\boxed{\frac{40}{7} \text{ hours}} or 557 hours\boxed{5 \frac{5}{7} \text{ hours}}.

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