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A man borrowed a sum of money at a simple interest rate of 20% per annum. After 1 year, he paid a total of Kshs 850,000. How much did he borrow?

Mathematics

ScanSolve AI Answer

Answer

Kshs 708,333.33\text{Kshs } 708,333.33

Step-by-step solution

5 steps
  1. Identify the given information.

    The interest rate (RR) is 20%20\% per annum, which is 0.20 in decimal form.
    The time period (TT) is 1 year.
    The total amount paid (AA) after one year is Kshs 850,000.
    We need to find the principal amount borrowed (PP).

  2. Use the formula for the total amount with simple interest.

    The formula for the total amount (AA) after a certain time with simple interest is:

    A=P(1+RT)A = P(1 + RT)

    Where:
    AA = Total amount
    PP = Principal amount (initial amount borrowed)
    RR = Annual interest rate (as a decimal)
    TT = Time in years

  3. Substitute the given values into the formula.

    850,000=P(1+0.20×1)850,000 = P(1 + 0.20 \times 1) 850,000=P(1+0.20)850,000 = P(1 + 0.20) 850,000=P(1.20)850,000 = P(1.20)
  4. Solve for PP.

    To find PP, divide the total amount by 1.20:

    P=850,0001.20P = \frac{850,000}{1.20} P=708,333.333...P = 708,333.333...
  5. Round the answer to two decimal places for currency.

    P≈708,333.33P \approx 708,333.33

    The man borrowed Kshs 708,333.33.

    The amount borrowed was Kshs 708,333.33\text{Kshs } 708,333.33.

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