A quadrilateral has interior angles of 2(x-10), 4(x+5), 5(x+4), and (x-20) degrees. Find the measure of the exterior angles.

The sum of the interior angles of a quadrilateral is $360^\circ$.
The given angles are $2(x-10)$, $4(x+5)$, $5(x+4)$, and $(x-20)$.

Expand the terms:

Combine like terms:

Divide by 12:

Substitute $x=30$ into each angle expression:
Angle A: $2(x-10) = 2(30-10) = 2(20) = 40^\circ$
Angle B: $4(x+5) = 4(30+5) = 4(35) = 140^\circ$
Angle C: $5(x+4) = 5(30+4) = 5(34) = 170^\circ$
Angle D: $(x-20) = (30-20) = 10^\circ$

The sum of an interior angle and its corresponding exterior angle is $180^\circ$.
Exterior Angle A: $180^\circ - 40^\circ = 140^\circ$
Exterior Angle B: $180^\circ - 140^\circ = 40^\circ$
Exterior Angle C: $180^\circ - 170^\circ = 10^\circ$
Exterior Angle D: $180^\circ - 10^\circ = 170^\circ$

The exterior angles of the quadrilateral are $\boxed{140^\circ, 40^\circ, 10^\circ, 170^\circ}$.

This is a problem involving work, men, days, and hours. We can use the formula:

Let $M_1, D_1, H_1, W_1$ be the values for the first scenario and $M_2, D_2, H_2, W_2$ for the second scenario.
Given:
$M_1 = 4$ men
$W_1 = 2$ acres
$D_1 = 3$ days
$H_1 = 4$ hours/day

$M_2 = ?$ men
$W_2 = 5$ acres
$D_2 = 4$ days
$H_2 = 3$ hours/day

Substitute the given values:

Simplify the left side:

Cross-multiply:

Divide by 12:

Therefore, $\boxed{10 \text{ men}}$ are required.

For similar solids, the ratio of their surface areas is equal to the square of the ratio of their corresponding linear dimensions.
Let $A_s$ be the surface area of the smaller bottle and $A_L$ be the surface area of the larger bottle.
$A_s = 12 \text{ cm}^2$
$A_L = 108 \text{ cm}^2$
The ratio of surface areas is:

If the ratio of surface areas is $k^2$, then the ratio of linear dimensions is $k$.

For similar solids, the ratio of their volumes is equal to the cube of the ratio of their corresponding linear dimensions.

We are given that the volume of the larger bottle ($V_L$) is $810 \text{ cm}^3$.

Multiply both sides by $810 \text{ cm}^3$:

The volume of the smaller bottle is $\boxed{30 \text{ cm}^3}$.