A rectangular invitation card measuring 120 mm by 15 cm has a circular photo with a diameter of 80 mm printed on it. Calculate: (a) The area of the invitation card. (b) The area of the invitation card

The width of the card is $120 \text{ mm}$.
The length of the card is $15 \text{ cm}$.
To convert centimeters to millimeters, multiply by 10:

$$15 \text{ cm} = 15 \times 10 \text{ mm} = 150 \text{ mm}$$

$$\text{Area of rectangle} = 150 \text{ mm} \times 120 \text{ mm}$$ $$\text{Area of rectangle} = 18000 \text{ mm}^2$$

The area of the rectangular invitation card is $\boxed{\text{18000 mm}^2}$.

The diameter of the circular photo is $80 \text{ mm}$.
The radius is half of the diameter:

$$\text{Radius} = \frac{80 \text{ mm}}{2} = 40 \text{ mm}$$

$$\text{Area of circle} = 3.14 \times (40 \text{ mm})^2$$ $$\text{Area of circle} = 3.14 \times 1600 \text{ mm}^2$$ $$\text{Area of circle} = 5024 \text{ mm}^2$$

$$\text{Area without photo} = \text{Area of rectangle} - \text{Area of circle}$$ $$\text{Area without photo} = 18000 \text{ mm}^2 - 5024 \text{ mm}^2$$ $$\text{Area without photo} = 12976 \text{ mm}^2$$

The area of the rectangular invitation card without the photo is $\boxed{\text{12976 mm}^2}$.