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A rubrics cube measures 4.5 cm on each side. Find its volume. Using a four-figure mathematical table, evaluate sqrt(0.009441).

Mathematics

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6. A rubrics cube measures 4.5 cm4.5\text{ cm} on each side. Find its volume.

  1. Identify the formula for the volume of a cube.

    The volume VV of a cube with side length ss is given by V=s3V = s^3.

  2. Substitute the given side length into the formula.

    s=4.5 cms = 4.5\text{ cm}

    V=(4.5 cm)3V = (4.5\text{ cm})^3
  3. Calculate the volume.

    V=4.5×4.5×4.5 cm3V = 4.5 \times 4.5 \times 4.5\text{ cm}^3 V=20.25×4.5 cm3V = 20.25 \times 4.5\text{ cm}^3 V=91.125 cm3V = 91.125\text{ cm}^3

    The volume of the cube is 91.125 cm3\boxed{91.125\text{ cm}^3}.

    7. Using a four-figure mathematical table, evaluate 0.009441\sqrt{0.009441}.

    To evaluate 0.009441\sqrt{0.009441} using a four-figure mathematical table, one would typically use logarithms.
    Let x=0.009441x = \sqrt{0.009441}.
    Then log⁡x=log⁡(0.009441)=12log⁡(0.009441)\log x = \log(\sqrt{0.009441}) = \frac{1}{2} \log(0.009441).

  4. Find the logarithm of 0.009441.

    log⁡(0.009441)=3‾.9750\log(0.009441) = \overline{3}.9750 (using a calculator for precision, as tables are not available).
    The characteristic is −3-3. The mantissa for 9441 is approximately 0.9750.

  5. Divide the logarithm by 2.

    log⁡x=12(3‾.9750)\log x = \frac{1}{2} (\overline{3}.9750)

    To divide 3‾.9750\overline{3}.9750 by 2, we rewrite the characteristic:

    3‾.9750=−3+0.9750=−4+1.9750\overline{3}.9750 = -3 + 0.9750 = -4 + 1.9750 log⁡x=12(−4+1.9750)=−2+0.9875=2‾.9875\log x = \frac{1}{2} (-4 + 1.9750) = -2 + 0.9875 = \overline{2}.9875
  6. Find the antilog of 2‾.9875\overline{2}.9875.

    Antilog(2‾.9875\overline{2}.9875) is the number whose logarithm is 2‾.9875\overline{2}.9875.
    Using a calculator for precision (as a four-figure table would give an approximation):
    102‾.9875=10−2+0.9875=10−2×100.9875≈0.01×9.71610^{\overline{2}.9875} = 10^{-2 + 0.9875} = 10^{-2} \times 10^{0.9875} \approx 0.01 \times 9.716

    x≈0.09716x \approx 0.09716

    Rounding to four significant figures, as would be typical for a four-figure table:

    x≈0.09716x \approx 0.09716

    The value is 0.09716\boxed{0.09716}.

    8. Using a scientific calculator to find 49.9\sqrt{49.9} correct to 3 significant figures.

  7. Calculate the square root using a calculator.

    49.9≈7.06400722\sqrt{49.9} \approx 7.06400722
  8. Round the result to 3 significant figures.

    The first three significant figures are 7, 0, 6. The fourth digit is 4, which is less than 5, so we round down.

    7.067.06

    The value of 49.9\sqrt{49.9} correct to 3 significant figures is 7.06\boxed{7.06}.

    9. Express 0.09364 in standard form.

  9. Move the decimal point to get a number between 1 and 10.

    Move the decimal point 2 places to the right to get 9.364.

  10. Determine the power of 10.

    Since the decimal point was moved 2 places to the right, the power of 10 is −2-2.

    0.09364=9.364×10−20.09364 = 9.364 \times 10^{-2}

    The number in standard form is 9.364×10−2\boxed{9.364 \times 10^{-2}}.

    10. Using a four-figure mathematical table evaluate 94.36\sqrt{94.36}.

    To evaluate 94.36\sqrt{94.36} using a four-figure mathematical table, one would typically use logarithms.
    Let x=94.36x = \sqrt{94.36}.
    Then log⁡x=log⁡(94.36)=12log⁡(94.36)\log x = \log(\sqrt{94.36}) = \frac{1}{2} \log(94.36).

  11. Find the logarithm of 94.36.

    log⁡(94.36)=1.9748\log(94.36) = 1.9748 (using a calculator for precision, as tables are not available).
    The characteristic is 1. The mantissa for 9436 is approximately 0.9748.

  12. Divide the logarithm by 2.

    log⁡x=12(1.9748)=0.9874\log x = \frac{1}{2} (1.9748) = 0.9874
  13. Find the antilog of 0.9874.

    Antilog(0.9874) is the number whose logarithm is 0.9874.
    Using a calculator for precision (as a four-figure table would give an approximation):
    100.9874≈9.71310^{0.9874} \approx 9.713
    Rounding to four significant figures, as would be typical for a four-figure table:

    x≈9.713x \approx 9.713

    The value is 9.713\boxed{9.713}.

    11. Given Express the square of 89 in standard form.

  14. Calculate the square of 89.

    892=89×89=792189^2 = 89 \times 89 = 7921
  15. Express the result in standard form.

    Move the decimal point 3 places to the left to get 7.921.
    Since the decimal point was moved 3 places to the left, the power of 10 is 3.

    7921=7.921×1037921 = 7.921 \times 10^3

    The square of 89 in standard form is 7.921×103\boxed{7.921 \times 10^3}.

    12. Express 1 in logarithmic notation base 7.

  16. Recall the property of logarithms that states log⁡bb=1\log_b b = 1.

    This means that the logarithm of a number to the same base is always 1.

  17. Apply this property with base 7.

    Therefore, 1=log⁡771 = \log_7 7.

    The number 1 in logarithmic notation base 7 is log⁡77\boxed{\log_7 7}.

    13. Evaluate (125)−23(125)^{-\frac{2}{3}}.

  18. Apply the negative exponent rule

    a−n=1ana^{-n} = \frac{1}{a^n}.

    (125)−23=1(125)23(125)^{-\frac{2}{3}} = \frac{1}{(125)^{\frac{2}{3}}}
  19. Apply the fractional exponent rule

    amn=(an)ma^{\frac{m}{n}} = (\sqrt[n]{a})^m.

    (125)23=(1253)2(125)^{\frac{2}{3}} = (\sqrt[3]{125})^2
  20. Calculate the cube root of 125.

    1253=5(since 5×5×5=125)\sqrt[3]{125} = 5 \quad (\text{since } 5 \times 5 \times 5 = 125)
  21. Square the result.

    52=255^2 = 25
  22. Substitute back into the expression.

    125\frac{1}{25}

    The evaluated expression is 125\boxed{\frac{1}{25}}.

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