A running track has a rectangular middle section and two semi-circular ends. The length of the straight sides is 110 m and the diameter of the semi-circles is 70 m. Calculate the perimeter and area of

The running track consists of a rectangular middle section and two semi-circular ends.
The length of the straight sides (length of the rectangle) is $L = 110$ m.
The diameter of each semi-circle is $D = 70$ m.
The radius of each semi-circle is $r = \frac{D}{2} = \frac{70}{2} = 35$ m.
The width of the rectangular section is equal to the diameter of the semi-circles, $W = 70$ m.
Use $\pi = \frac{22}{7}$.

The distance round the field is the sum of the lengths of the two straight sides and the circumference of the two semi-circular ends. The two semi-circular ends together form a full circle.
Perimeter $P = 2 \times L + \text{Circumference of a full circle}$
The circumference of a full circle is $\pi D$.

Substitute the given values:

The distance round the field is $\boxed{440 \text{ m}}$.

The area of the field is the sum of the area of the rectangular middle section and the area of the two semi-circular ends. The two semi-circular ends together form a full circle.
Area $A = \text{Area of rectangle} + \text{Area of a full circle}$
The area of the rectangle is $L \times W$.
The area of a full circle is $\pi r^2$.

Substitute the given values:

The area of the field is $\boxed{11550 \text{ m}^2}$.