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A school has N 100.00 to buy apples. Each apple costs N 12.00. How many apples can the school buy without spending more than N$ 100.00?

Mathematics

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Answer

8 apples\text{8 apples}

Step-by-step solution

3 steps

Here's how to solve the problem:

  1. Identify the total amount of money available and the cost per apple.

    The school has N$ 100.00. Each apple costs N$ 12.00.

  2. Divide the total money by the cost per apple to find the maximum number of apples that can be bought.

    Number of apples=Total moneyCost per apple\text{Number of apples} = \frac{\text{Total money}}{\text{Cost per apple}}

    Number of apples=N$ 100.00N$ 12.00\text{Number of apples} = \frac{\text{N\$ } 100.00}{\text{N\$ } 12.00}

    Number of apples=8.333...\text{Number of apples} = 8.333...

  3. Since you cannot buy a fraction of an apple, take the whole number part of the result.

    The school can buy 8 apples.

    The school can buy 8 apples\text{8 apples}.

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