A section of a road measuring 4.5 km is represented by a length of 9 cm on a map. What is the scale on the map in ratio form?

The actual distance between Khalid's shop and Ole Sankale's hardware is $900 \text{ m}$.
To determine the scale used for the drawing, the length of the line XY on the drawing is required.

The length of the line XY on the drawing is not provided in the problem. Without this measurement, the scale cannot be calculated.

13.

Map length = $9 \text{ cm}$
Actual length = $4.5 \text{ km}$

Since $1 \text{ km} = 1000 \text{ m}$ and $1 \text{ m} = 100 \text{ cm}$, then $1 \text{ km} = 1000 \times 100 = 100000 \text{ cm}$.

actual length).

Divide both sides of the ratio by 9:

The scale on the map is $\boxed{1:50000}$.

14.

Actual length = $600 \text{ m}$
Actual width = $350 \text{ m}$

A reasonable drawing size for paper is typically between a few centimeters and about $30-40 \text{ cm}$ for the longest side.

• A. Scale 1:100 Drawing length = $\frac{60000 \text{ cm}}{100} = 600 \text{ cm}$ (or $6 \text{ m}$) This is too large for a drawing on paper.

• B. Scale 1:1 000 Drawing length = $\frac{60000 \text{ cm}}{1000} = 60 \text{ cm}$ Drawing width = $\frac{35000 \text{ cm}}{1000} = 35 \text{ cm}$ This drawing ($60 \text{ cm} \times 35 \text{ cm}$) is quite large, possibly for a poster, but generally too big for standard paper.

• C. Scale 1:10 000 Drawing length = $\frac{60000 \text{ cm}}{10000} = 6 \text{ cm}$ Drawing width = $\frac{35000 \text{ cm}}{10000} = 3.5 \text{ cm}$ This drawing ($6 \text{ cm} \times 3.5 \text{ cm}$) is a very reasonable size for a drawing on a standard piece of paper, allowing for detail.

• D. Scale 1:100 000 Drawing length = $\frac{60000 \text{ cm}}{100000} = 0.6 \text{ cm}$ Drawing width = $\frac{35000 \text{ cm}}{100000} = 0.35 \text{ cm}$ This drawing ($0.6 \text{ cm} \times 0.35 \text{ cm}$) is too small to show any meaningful detail.

The scale that produces the most appropriate drawing size for a piece of paper is $1:10000$.
The most appropriate scale is $\boxed{\text{C. } 1:10000}$.

15.

Map length = $4 \text{ cm}$
Actual length = $16 \text{ km}$

Since $1 \text{ km} = 100000 \text{ cm}$:

actual length).

Divide both sides of the ratio by 4:

The scale used on the map is $\boxed{1:400000}$.