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A set of particle sizes are measured in divisions: 4, 5, 6, 7, 8, 10, 12, 14, 16, 17, 18, 19, 20, 22, 23, 24, 25. The calibration factor is double the square root of 16. a) Calculate the calibration f

Mathematics

ScanSolve AI Answer

Answers

2 parts
a
8
b
113.65

Step-by-step solution

5 steps

Part a· 1 step

Step 1: Calculate the calibration factor.

The calibration factor is double the square root of 16.

Calibration factor=2×16=2×4=8\text{Calibration factor} = 2 \times \sqrt{16} = 2 \times 4 = 8
  1. Calculate the actual particle size for each number of divisions.

    The actual particle size is found by multiplying the number of divisions by the calibration factor (8).

    No of division45678101214161718192022232425
    Actual particle size32404856648096112128136144152160176184192200

    The calibration factor is 8\boxed{8}.

Part b113.65

Step 1: Determine the mid-class (X) for each particle size range.

  • For 0-50: X=0+502=25X = \frac{0+50}{2} = 25
  • For 51-100: X=51+1002=75.5X = \frac{51+100}{2} = 75.5
  • For 101-150: X=101+1502=125.5X = \frac{101+150}{2} = 125.5
  • For 151-200: X=151+2002=175.5X = \frac{151+200}{2} = 175.5
  1. Determine the frequency (F) for each class by counting the actual particle sizes from part (a) that fall into each range.

    The actual particle sizes are: 32, 40, 48, 56, 64, 80, 96, 112, 128, 136, 144, 152, 160, 176, 184, 192, 200.

    • 0-50: {32, 40, 48}   ⟹  F=3\implies F = 3
    • 51-100: {56, 64, 80, 96}   ⟹  F=4\implies F = 4
    • 101-150: {112, 128, 136, 144}   ⟹  F=4\implies F = 4
    • 151-200: {152, 160, 176, 184, 192, 200}   ⟹  F=6\implies F = 6
  2. Calculate Frequency ×\times mid class (FX) for each class.

    Particle sizeMid class (X)Frequency (F)Frequency X mid class (FX)
    0-5025325×3=7525 \times 3 = 75
    51-10075.5475.5×4=30275.5 \times 4 = 302
    101-150125.54125.5×4=502125.5 \times 4 = 502
    151-200175.56175.5×6=1053175.5 \times 6 = 1053
  3. Calculate the sum of frequencies (∑F\sum F) and the sum of (FX) (∑FX\sum FX).

    ∑F=3+4+4+6=17\sum F = 3 + 4 + 4 + 6 = 17 ∑FX=75+302+502+1053=1932\sum FX = 75 + 302 + 502 + 1053 = 1932
  4. Calculate the mean particle size using the formula ∑FX∑F\frac{\sum FX}{\sum F}.

    Mean particle size=193217≈113.65\text{Mean particle size} = \frac{1932}{17} \approx 113.65

    The mean particle size is 113.65\boxed{113.65}.

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