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A shopkeeper sold 6 pencils at Rs 8 each. Sunayana paid Rs 50. How much change did she get?

Mathematics

ScanSolve AI Answer

Step-by-step solution

10 steps

8. a)

i) Write a mathematical expression to show the above information.

  1. Calculate the total cost of the pencils.

    Cost of pencils =6×8= 6 \times 8

  2. Subtract the total cost from the amount Sunayana paid.

    The mathematical expression is:

    50−(6×8)50 - (6 \times 8)

    ii) Simplify the expression and find how much change did the shopkeeper return her?

  3. Perform the multiplication inside the parentheses.

    50−(6×8)=50−4850 - (6 \times 8) = 50 - 48
  4. Perform the subtraction.

    50−48=250 - 48 = 2

    The shopkeeper returned Rs 2.

    Rs 2\boxed{\text{Rs } 2}

    8. b)

    i) Write a mathematical expression for the above information.

  5. Calculate the total cost of the exercise books.

    Cost of exercise books =6×40= 6 \times 40

  6. Add the cost of the eraser to the cost of the books to find the total expenditure.

    Total expenditure =(6×40)+10= (6 \times 40) + 10

  7. Subtract the total expenditure from the amount Anil paid.

    The mathematical expression is:

    500−((6×40)+10)500 - ((6 \times 40) + 10)

    ii) How much change did the shopkeeper return him?

  8. Perform the multiplication inside the inner parentheses.

    500−((6×40)+10)=500−(240+10)500 - ((6 \times 40) + 10) = 500 - (240 + 10)
  9. Perform the addition inside the parentheses.

    500−(240+10)=500−250500 - (240 + 10) = 500 - 250
  10. Perform the subtraction.

    500−250=250500 - 250 = 250

    The shopkeeper returned Rs 250.

    Rs 250\boxed{\text{Rs } 250}
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