This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Here's the solution for Question 30:
Question 30(a): Let the price of one pencil be Ksh. i) Write an expression for the price of one pen. A pen costs Ksh 4 more than a pencil. Price of one pen = Ksh.
ii) Write an expression for the price of one pencil. Price of one pencil = Ksh.
Question 30(b): Kering purchased pens for Ksh 180. The price of one pen is Ksh.
Naraya purchased pencils for Ksh 200. The price of one pencil is Ksh.
From part (a), we know that the price of one pen is and the price of one pencil is . Therefore, we can set up the equation based on the relationship: Price of one pen = Price of one pencil + 4.
Step 1: Form the equation.
Step 2: Solve the equation for . Multiply the entire equation by to eliminate denominators. Rearrange into a standard quadratic form : Divide the entire equation by 24:
Step 3: Factor the quadratic equation. We need two numbers that multiply to -16 and add to -6. These numbers are -8 and 2. This gives two possible solutions for :
Step 4: Choose the valid value for . Since represents the price of a pencil, it must be a positive value. Also, the number of items purchased and must be positive. If , the price would be negative, and the number of pens would be , which is not possible. Therefore, the valid value is .
The value of is .
Question 30(c): Step 1: Determine the original and new prices. From part (b), . Original price of one pencil = Ksh. Original price of one pen = Ksh.
The price of a pen went up by 25%. New price of one pen = Ksh. The price of a pencil remained unchanged. New price of one pencil = 8 Ksh.
Step 2: Set up equations based on the given conditions. Let be the number of pens bought by the school. Let be the number of pencils bought by the school.
Condition 1: The school spent the same amount of money on pens as on pencils.
Condition 2: The total number of both pens and pencils bought was 46.
Step 3: Solve the system of equations for . From Equation 2, express in terms of : Substitute this into Equation 1:
The number of pens bought by the school is .
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Here's the solution for Question 30: Question 30(a): Let the price of one pencil be x Ksh.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.