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A stadium has 52,345 seats. If 48,912 tickets were sold, how many seats were not sold? Town A has a population of 23,456. Town B has 15,789 more people than Town A. How many people live in Town B? A p

Mathematics

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Here are the answers to your questions:

15)

  1. Identify the total number of seats in the stadium.

    Total seats = 52,345

  2. Identify the number of tickets sold.

    Tickets sold = 48,912

  3. Calculate the number of seats that were not sold (empty seats).

    Number of unsold seats = Total seats - Tickets sold

    =52,345−48,912= 52,345 - 48,912 =3,433= 3,433

    The question asks "How many seats were there in the stadium?". Based on the numbers provided, it is likely asking for the number of unsold seats.
    The number of seats in the stadium is 52,345 seats\boxed{\text{52,345 seats}}.
    The number of unsold seats is 3,433 seats\boxed{\text{3,433 seats}}.

    16)

  4. Identify the population of Town A.

    Population of Town A = 23,456

  5. Identify how many more people Town B has than Town A.

    Difference = 15,789

  6. Calculate the total population of Town B.

    Population of Town B = Population of Town A + Difference

    =23,456+15,789= 23,456 + 15,789 =39,245= 39,245

    The total population of Town B is 39,245\boxed{\text{39,245}}.

    17)

  7. Identify the distance flown on Tuesday.

    Tuesday's distance = 8,345 km8,345 \text{ km}

  8. Identify how much the distance was shortened on Wednesday from Tuesday's distance.

    Shortened distance = 75 km75 \text{ km}

  9. Calculate the distance flown on Wednesday.

    Wednesday's distance = Tuesday's distance - Shortened distance

    =8,345 km−75 km= 8,345 \text{ km} - 75 \text{ km} =8,270 km= 8,270 \text{ km}

    The pilot flew 8,270 km\boxed{\text{8,270 km}} on Wednesday.

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