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A tank of capacity 9600 litres is filled by tap R in 9 minutes, tap S in 12 minutes and emptied by tap T in 6 minutes. What fraction of the tank is filled in 1 minute if R and S are opened?

Mathematics

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Answers

4 parts
a

1066.67 litres1066.67 \text{ litres}

b

1600 litres1600 \text{ litres}

c

1866.67 litres1866.67 \text{ litres}

d

36 minutes36 \text{ minutes}

Step-by-step solution

6 steps

Here's the solution to the problem:

Given:
Tank capacity = 9600 litres
Tap R fills the tank in 9 minutes.
Tap S fills the tank in 12 minutes.
Tap T empties the tank in 6 minutes.

Part a· 1 step

How much is put in the tank by tap R in one minute?

  1. Calculate the rate of tap R.

    Tap R fills 9600 litres in 9 minutes.

    Rate of R=Total capacityTime taken by R=9600 litres9 minutes\text{Rate of R} = \frac{\text{Total capacity}}{\text{Time taken by R}} = \frac{9600 \text{ litres}}{9 \text{ minutes}} Rate of R=1066.67 litres/minute\text{Rate of R} = 1066.67 \text{ litres/minute}

    Tap R puts approximately 1066.67 litres into the tank in one minute.

    1066.67 litres\boxed{1066.67 \text{ litres}}

Part b

1600 litres1600 \text{ litres}

How much is drawn from the tank by tap T?

  1. Calculate the rate of tap T.

    Tap T empties 9600 litres in 6 minutes.

    Rate of T=Total capacityTime taken by T=9600 litres6 minutes\text{Rate of T} = \frac{\text{Total capacity}}{\text{Time taken by T}} = \frac{9600 \text{ litres}}{6 \text{ minutes}} Rate of T=1600 litres/minute\text{Rate of T} = 1600 \text{ litres/minute}

    Tap T draws 1600 litres from the tank in one minute.

    1600 litres\boxed{1600 \text{ litres}}

Part c

1866.67 litres1866.67 \text{ litres}

How many litres of water tap R and Tap S pour into the tank in one minute?

  1. Calculate the rate of tap S.

    Tap S fills 9600 litres in 12 minutes.

    Rate of S=Total capacityTime taken by S=9600 litres12 minutes\text{Rate of S} = \frac{\text{Total capacity}}{\text{Time taken by S}} = \frac{9600 \text{ litres}}{12 \text{ minutes}} Rate of S=800 litres/minute\text{Rate of S} = 800 \text{ litres/minute}
  2. Calculate the combined rate of tap R and tap S.

    Combined rate (R+S)=Rate of R+Rate of S\text{Combined rate (R+S)} = \text{Rate of R} + \text{Rate of S} Combined rate (R+S)=1066.67 litres/minute+800 litres/minute\text{Combined rate (R+S)} = 1066.67 \text{ litres/minute} + 800 \text{ litres/minute} Combined rate (R+S)=1866.67 litres/minute\text{Combined rate (R+S)} = 1866.67 \text{ litres/minute}

    Tap R and Tap S pour approximately 1866.67 litres into the tank in one minute.

    1866.67 litres\boxed{1866.67 \text{ litres}}

Part d

36 minutes36 \text{ minutes}

How long will it take to fill the tank if all taps are left open at the same time?

  1. Calculate the net filling rate when all taps are open.

    The net rate is the sum of filling rates minus the emptying rate.

    Net rate=Rate of R+Rate of S−Rate of T\text{Net rate} = \text{Rate of R} + \text{Rate of S} - \text{Rate of T} Net rate=1066.67 litres/minute+800 litres/minute−1600 litres/minute\text{Net rate} = 1066.67 \text{ litres/minute} + 800 \text{ litres/minute} - 1600 \text{ litres/minute} Net rate=1866.67 litres/minute−1600 litres/minute\text{Net rate} = 1866.67 \text{ litres/minute} - 1600 \text{ litres/minute} Net rate=266.67 litres/minute\text{Net rate} = 266.67 \text{ litres/minute}
  2. Calculate the time taken to fill the tank.

    Time=Total capacityNet rate\text{Time} = \frac{\text{Total capacity}}{\text{Net rate}} Time=9600 litres266.67 litres/minute\text{Time} = \frac{9600 \text{ litres}}{266.67 \text{ litres/minute}} Time=36 minutes\text{Time} = 36 \text{ minutes}

    It will take 36 minutes to fill the tank if all taps are left open at the same time.

    36 minutes\boxed{36 \text{ minutes}}
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