This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Hey NLE — ready when you are. Here are the solutions to the questions from Section A. 1. Given: Marked price (inclusive of VAT and NHIL) = GHC 1,517.50. VAT rate = 12(1)/(2)\% = 0.125. NHIL rate = 2(1)/(2)\% = 0.025. Let P be the cost of the television set (VAT and NHIL exclusive). The total percentage charged on P is 100\% + 12.5\% + 2.5\% = 115\%. So, 1.15P = 1517.50. a) The cost of the television set (VAT and NHIL exclusive). Step 1: Calculate P. P = (1517.50)/(1.15) P = 1319.5652... Rounding to two decimal places for currency: P = GHC 1319.57 b) The NHIL charged. Step 1: Calculate NHIL as 2.5\% of P. NHIL = 0.025 × 1319.5652... NHIL = 32.9891... Rounding to two decimal places: NHIL = GHC 32.99 c) The VAT charged. Step 1: Calculate VAT as 12.5\% of P. VAT = 0.125 × 1319.5652... VAT = 164.9456... Rounding to two decimal places: VAT = GHC 164.95 2. The electrical resistance R varies directly as its length L and inversely as the square of its radius r. This can be written as R = k (L)/(r^2), where k is the constant of proportionality. Given: L_1 = 500 m, r_1 = 0.2 cm, R_1 = 30 ohms. Convert r_1 to meters: 0.2 cm = 0.002 m. i) Find the rule connecting R, L and r. Step 1: Substitute the given values into the formula to find k. 30 = k (500)/((0.002)^2) 30 = k (500)/(0.000004) 30 = k × 125,000,000 Step 2: Solve for k. k = (30)/(125,000,000) = (3)/(12,500,000) = 0.00000024 The rule connecting R, L and r is R = 0.00000024 (L)/(r^2). ii) Evaluate the resistance of the same type of copper wire 750m long and radius 0.25cm. Given: L_2 = 750 m, r_2 = 0.25 cm. Convert r_2 to meters: 0.25 cm = 0.0025 m. Step 1: Substitute k, L_2, and r_2 into the rule. R_2 = 0.00000024 (750)/((0.0025)^2) R_2 = 0.00000024 (750)/(0.00000625) Step 2: Calculate the resistance R_2. R_2 = 0.00000024 × 120,000,000 R_2 = 28.8 ohms 3. a) Copy and complete the multiplication table for modulo 6 on the set \2,3,4,5\. The operation a b means $(a × b