A tortoise walked 10 rac12 m on Monday, 8 rac14 m on Tuesday, 11 rac12 m on Wednesday, 9 rac12 m on Thursday, and 6 rac14 m on Friday. What was the total distance the tortoise walked in 5 days?

The tortoise walked the following distances:

• Monday: $10\frac{1}{2}$ m
• Tuesday: $8\frac{1}{4}$ m
• Wednesday: $11\frac{1}{2}$ m
• Thursday: $9\frac{1}{2}$ m
• Friday: $6\frac{1}{4}$ m

Sum of whole numbers $= 10 + 8 + 11 + 9 + 6$

$$10 + 8 + 11 + 9 + 6 = 44$$

Sum of fractions $= \frac{1}{2} + \frac{1}{4} + \frac{1}{2} + \frac{1}{2} + \frac{1}{4}$
To add these fractions, find a common denominator, which is 4.
Convert $\frac{1}{2}$ to $\frac{2}{4}$:

$$\frac{2}{4} + \frac{1}{4} + \frac{2}{4} + \frac{2}{4} + \frac{1}{4} = \frac{2+1+2+2+1}{4} = \frac{8}{4}$$

Simplify the sum of fractions:

$$\frac{8}{4} = 2$$

Total distance $= \text{Sum of whole numbers} + \text{Sum of fractions}$
Total distance $= 44 + 2 = 46$ m

The tortoise walked a total of 46 meters in 5 days.

The total distance the tortoise walked is $\text{46 m}$.