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A village has a population of 20,000. If the population grows at a rate of R% per annum, the population after T years is given by the formula P_T = P(1 + R/100)^T. a) Find the population after 2 years

Mathematics

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3 parts
a

PT=P(1+R100)TP_T = P \left(1 + \frac{R}{100}\right)^T

b

2 years\text{2 years}

c
1218

Step-by-step solution

6 steps

Here is the solution to question 3:

3. Population Growth

Part a

If the initial population is PP, growth rate is RR per annum, and population after TT years is PTP_T, the formula to find PTP_T is

PT=P(1+R100)TP_T = P \left(1 + \frac{R}{100}\right)^T

The formula is PT=P(1+R100)T\boxed{P_T = P \left(1 + \frac{R}{100}\right)^T}.

Part b

2 years\text{2 years}

After how many years will the population of the village be 20,808?

  1. Identify the given values.

    Initial population, P=20000P = 20000
    Annual growth rate, R=2%R = 2\% (from the problem description)
    Population after TT years, PT=20808P_T = 20808

  2. Use the population growth formula.

    PT=P(1+R100)TP_T = P \left(1 + \frac{R}{100}\right)^T

    Substitute the given values:

    20808=20000(1+2100)T20808 = 20000 \left(1 + \frac{2}{100}\right)^T 20808=20000(1+0.02)T20808 = 20000 \left(1 + 0.02\right)^T 20808=20000(1.02)T20808 = 20000 (1.02)^T
  3. Solve for TT.

    2080820000=(1.02)T\frac{20808}{20000} = (1.02)^T 1.0404=(1.02)T1.0404 = (1.02)^T

    Recognize that 1.0404=(1.02)21.0404 = (1.02)^2.

    (1.02)2=(1.02)T(1.02)^2 = (1.02)^T

    Therefore, T=2T = 2 years.

    The population will be 20,808 after 2 years\boxed{\text{2 years}}.

Part c1218

If the population increases at the rate of 3% per annum, by what number will the population of the village be increased in 2 years?

  1. Identify the given values for this part.

    Initial population, P=20000P = 20000
    New annual growth rate, R=3%R = 3\%
    Time, T=2T = 2 years

  2. Calculate the population after 2 years (PTP_T).

    PT=P(1+R100)TP_T = P \left(1 + \frac{R}{100}\right)^T

    Substitute the values:

    PT=20000(1+3100)2P_T = 20000 \left(1 + \frac{3}{100}\right)^2 PT=20000(1+0.03)2P_T = 20000 (1 + 0.03)^2 PT=20000(1.03)2P_T = 20000 (1.03)^2 PT=20000×1.0609P_T = 20000 \times 1.0609 PT=21218P_T = 21218
  3. Calculate the increase in population.

    Increase = Final population - Initial population
    Increase = PT−PP_T - P
    Increase = 21218−2000021218 - 20000
    Increase = 1218

    The population will be increased by 1218\boxed{1218}.

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