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A woman spent 1/4 of her salary on drugs and 1/8 on rent, what fraction of her salary is left? b. Simplify 2-2/3 x 1 1/2 - 4 4/5

Mathematics

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Question 1a: A woman spent 14\frac{1}{4} of her salary on drugs and 18\frac{1}{8} on rent, what fraction of her salary is left?

  1. Find the total fraction of salary spent.

    To do this, we add the fractions spent on drugs and rent.

    Total spent=14+18\text{Total spent} = \frac{1}{4} + \frac{1}{8}

    To add these fractions, find a common denominator, which is 8.

    Total spent=1×24×2+18=28+18=2+18=38\text{Total spent} = \frac{1 \times 2}{4 \times 2} + \frac{1}{8} = \frac{2}{8} + \frac{1}{8} = \frac{2+1}{8} = \frac{3}{8}
  2. Calculate the fraction of salary left.

    The total salary can be represented as 1 (or 88\frac{8}{8}). To find the fraction left, subtract the total fraction spent from 1.

    Fraction left=1−38\text{Fraction left} = 1 - \frac{3}{8} Fraction left=88−38=8−38=58\text{Fraction left} = \frac{8}{8} - \frac{3}{8} = \frac{8-3}{8} = \frac{5}{8}

    The fraction of her salary left is 58\boxed{\frac{5}{8}}.

    Question 1b: Simplify 223×112−4452 \frac{2}{3} \times 1 \frac{1}{2} - 4 \frac{4}{5}

  3. Convert all mixed numbers to improper fractions.

    223=(2×3)+23=6+23=832 \frac{2}{3} = \frac{(2 \times 3) + 2}{3} = \frac{6+2}{3} = \frac{8}{3} 112=(1×2)+12=2+12=321 \frac{1}{2} = \frac{(1 \times 2) + 1}{2} = \frac{2+1}{2} = \frac{3}{2} 445=(4×5)+45=20+45=2454 \frac{4}{5} = \frac{(4 \times 5) + 4}{5} = \frac{20+4}{5} = \frac{24}{5}
  4. Perform the multiplication.

    83×32\frac{8}{3} \times \frac{3}{2}

    We can cancel out the 3s and simplify the 8 and 2.

    83×32=82=4\frac{8}{\cancel{3}} \times \frac{\cancel{3}}{2} = \frac{8}{2} = 4
  5. Perform the subtraction.

    Now we have 4−2454 - \frac{24}{5}.
    To subtract, find a common denominator, which is 5.

    4−245=4×55−245=205−2454 - \frac{24}{5} = \frac{4 \times 5}{5} - \frac{24}{5} = \frac{20}{5} - \frac{24}{5} =20−245=−45= \frac{20 - 24}{5} = \frac{-4}{5}

    The simplified expression is −45\boxed{-\frac{4}{5}}.

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