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Simplify the following expressions: a) (1/2 2/3) + (1/2 of 3/4) + 1/2 b) (2.4 1.6 3.4) / (0.8 3.2 * 5.1)

Mathematics

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Answers

2 parts
a

{3,6,9,12,15,18}\{3, 6, 9, 12, 15, 18\}

b

{7,9,11,13,15,17,19}\{7, 9, 11, 13, 15, 17, 19\}

Step-by-step solution

3 steps

1. a)

Step 1: Simplify the terms in the brackets.
The expression is (12⋅23)+(12 of 34)+12(\frac{1}{2} \cdot \frac{2}{3}) + (\frac{1}{2} \text{ of } \frac{3}{4}) + \frac{1}{2}.
"of" means multiplication.

12×23=1×22×3=26=13\frac{1}{2} \times \frac{2}{3} = \frac{1 \times 2}{2 \times 3} = \frac{2}{6} = \frac{1}{3} 12×34=1×32×4=38\frac{1}{2} \times \frac{3}{4} = \frac{1 \times 3}{2 \times 4} = \frac{3}{8}

Step 2: Substitute the simplified terms back into the expression.

13+38+12\frac{1}{3} + \frac{3}{8} + \frac{1}{2}

Step 3: Find a common denominator for 3, 8, and 2, which is 24. Convert each fraction.

13=1×83×8=824\frac{1}{3} = \frac{1 \times 8}{3 \times 8} = \frac{8}{24} 38=3×38×3=924\frac{3}{8} = \frac{3 \times 3}{8 \times 3} = \frac{9}{24} 12=1×122×12=1224\frac{1}{2} = \frac{1 \times 12}{2 \times 12} = \frac{12}{24}

Step 4: Add the fractions.

824+924+1224=8+9+1224=2924\frac{8}{24} + \frac{9}{24} + \frac{12}{24} = \frac{8 + 9 + 12}{24} = \frac{29}{24}

The simplified expression is 2924\boxed{\frac{29}{24}}.

1. b)

Step 1: Rewrite the expression to simplify common factors.

2.4×1.6×3.40.8×3.2×5.1=2.40.8×1.63.2×3.45.1\frac{2.4 \times 1.6 \times 3.4}{0.8 \times 3.2 \times 5.1} = \frac{2.4}{0.8} \times \frac{1.6}{3.2} \times \frac{3.4}{5.1}

Step 2: Simplify each fraction.

2.40.8=248=3\frac{2.4}{0.8} = \frac{24}{8} = 3 1.63.2=1632=12\frac{1.6}{3.2} = \frac{16}{32} = \frac{1}{2} 3.45.1=3451=2×173×17=23\frac{3.4}{5.1} = \frac{34}{51} = \frac{2 \times 17}{3 \times 17} = \frac{2}{3}

Step 3: Multiply the simplified fractions.

3×12×23=3×1×22×3=66=13 \times \frac{1}{2} \times \frac{2}{3} = \frac{3 \times 1 \times 2}{2 \times 3} = \frac{6}{6} = 1

The simplified expression is 1\boxed{1}.

2. Given Σ={1,2,3,4,5,6,7,8,9,...,20}\Sigma = \{1, 2, 3, 4, 5, 6, 7, 8, 9, ..., 20\}.

Part a· 1 step

Set A = {Multiples of 3}

  1. Identify multiples of 3 within the set Σ\Sigma.

    Multiples of 3 are numbers that can be divided by 3 without a remainder.

    3×1=33 \times 1 = 3 3×2=63 \times 2 = 6 3×3=93 \times 3 = 9 3×4=123 \times 4 = 12 3×5=153 \times 5 = 15 3×6=183 \times 6 = 18

    The next multiple, 3×7=213 \times 7 = 21, is outside Σ\Sigma.
    Set A is {3,6,9,12,15,18}\boxed{\{3, 6, 9, 12, 15, 18\}}.

Part b

{7,9,11,13,15,17,19}\{7, 9, 11, 13, 15, 17, 19\}

Set B = {Odd numbers greater than 6}

  1. Identify numbers in Σ\Sigma that are greater than 6.

    These are {7,8,9,10,11,12,13,14,15,16,17,18,19,20}\{7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20\}.

  2. From this list, identify the odd numbers (numbers not divisible by 2).

    The odd numbers are 7,9,11,13,15,17,197, 9, 11, 13, 15, 17, 19.
    Set B is {7,9,11,13,15,17,19}\boxed{\{7, 9, 11, 13, 15, 17, 19\}}.

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