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Add: 749 + 356. 2. Change: 5.25 kg to grams. 3. The cost of 8 tomatoes is sh. 2400. What is the cost of 5 similar tomatoes.

Mathematics

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1. Add: 749+356749 + 356.

  1. Ongeza namba za vitengo.

    9+6=159 + 6 = 15

    Andika 5 na beba 1.

  2. Ongeza namba za makumi, ukijumuisha ule ulioubeba.

    4+5+1=104 + 5 + 1 = 10

    Andika 0 na beba 1.

  3. Ongeza namba za mamia, ukijumuisha ule ulioubeba.

    7+3+1=117 + 3 + 1 = 11

    Andika 11.

    Jumla ni:

    1105\boxed{\text{1105}}

    2. Change: 5.25 kg to grams.

  4. Tunajua kuwa kilogramu 1 ni sawa na gramu 1000.

    1 kg=1000 g1 \text{ kg} = 1000 \text{ g}
  5. Badilisha 5.25 kg kuwa gramu kwa kuzidisha na 1000.

    5.25 kg×1000gkg=5250 g5.25 \text{ kg} \times 1000 \frac{\text{g}}{\text{kg}} = 5250 \text{ g}

    5.25 kg ni sawa na:

    5250 g\boxed{\text{5250 g}}

    3. The cost of 8 tomatoes is sh. 2400. What is the cost of 5 similar tomatoes.

  6. Tafuta gharama ya nyanya moja.

    Gharama ya nyanya 1=Jumla ya gharamaIdadi ya nyanya\text{Gharama ya nyanya 1} = \frac{\text{Jumla ya gharama}}{\text{Idadi ya nyanya}} Gharama ya nyanya 1=sh. 24008=sh. 300\text{Gharama ya nyanya 1} = \frac{\text{sh. } 2400}{8} = \text{sh. } 300
  7. Tafuta gharama ya nyanya 5.

    Gharama ya nyanya 5=Gharama ya nyanya 1×5\text{Gharama ya nyanya 5} = \text{Gharama ya nyanya 1} \times 5 Gharama ya nyanya 5=sh. 300×5=sh. 1500\text{Gharama ya nyanya 5} = \text{sh. } 300 \times 5 = \text{sh. } 1500

    Gharama ya nyanya 5 ni:

    sh. 1500\boxed{\text{sh. 1500}}

    4. Describe the shaded region below.

    Eneo lililotiwa kivuli linaonyesha sehemu ya seti Q ambayo haimo katika seti P. Hii inajulikana kama tofauti ya seti au kikomplementi cha P kuhusiana na Q.

    Katika nukuu ya seti, hii inaweza kuwakilishwa kama:

    Q∖PauQ∩Pc\boxed{Q \setminus P \quad \text{au} \quad Q \cap P^c}

    5. Simplify: −8K+5y+3K−4y-8K + 5y + 3K - 4y.

  8. Panga upya maneno yanayofanana pamoja.

    −8K+3K+5y−4y-8K + 3K + 5y - 4y
  9. Unganisha maneno yanayofanana.

    (−8K+3K)+(5y−4y)(-8K + 3K) + (5y - 4y) −5K+1y-5K + 1y

    Maneno yaliyofupishwa ni:

    −5K+y\boxed{-5K + y}

    6. Construct 135∘135^\circ in the space below using a pair of compass, a ruler and a pencil.

    Hapa kuna hatua za kujenga pembe ya 135∘135^\circ:

  10. Chora mstari ulionyooka, sema AB.

    Weka alama ya O kwenye mstari huo.

  11. Kwa kutumia dira, jenga pembe ya 90∘90^\circ kwenye O.

    Ili kufanya hivyo, chora upinde mkubwa unaovuka mstari AB katika pointi mbili. Kutoka pointi hizo, chora upinde mwingine juu ya O ili zikutane. Unganisha O na sehemu ya makutano ya pinde hizo. Hebu tuseme mstari huu ni OC, hivyo ∠AOC=90∘\angle AOC = 90^\circ.

  12. Panua mstari AO upande wa kushoto hadi D, ili DOB iwe mstari ulionyooka.

    Sasa, ∠COB=90∘\angle COB = 90^\circ.

  13. Jenga pembe ya 45∘45^\circ kwa kugawanya pembe ya 90∘90^\circ (∠COB\angle COB) katika sehemu mbili sawa.

    Weka ncha ya dira kwenye C na chora upinde ndani ya ∠COB\angle COB. Kisha, weka ncha ya dira kwenye B na chora upinde mwingine unaovuka upinde wa kwanza. Unganisha O na sehemu ya makutano ya pinde hizi. Hebu tuseme mstari huu ni OE.

  14. Pembe ∠AOE\angle AOE sasa ni 90∘+45∘=135∘90^\circ + 45^\circ = 135^\circ.

    Pembe ya 135∘135^\circ imejengwa.

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