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Albus savings per month he plans to increase his savings in the ratio 4:3. How much will be the monthly savings after the increase?

Mathematics

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2 parts
1

9333.33 Shilingi\text{9333.33 Shilingi}

2

45.8 km\text{45.8 km}

Haya hapa masuluhisho ya maswali yako:

Swali la 1: Akiba ya Alfonse

  • Step 1: Tambua akiba ya awali na uwiano mpya. Akiba ya awali ya Alfonse ni 7000/=. Anapanga kuongeza akiba yake kwa uwiano wa 4:3, ambapo 4 inawakilisha akiba mpya na 3 inawakilisha akiba ya awali.

  • Step 2: Weka mlinganyo wa uwiano. Tutaweka SmpyaS_{mpya} kama akiba mpya.

    Smpya7000=43\frac{S_{mpya}}{7000} = \frac{4}{3}
  • Step 3: Tafuta akiba mpya. Ili kupata SmpyaS_{mpya}, zidisha pande zote mbili za mlinganyo kwa 7000:

    Smpya=43×7000S_{mpya} = \frac{4}{3} \times 7000 Smpya=280003S_{mpya} = \frac{28000}{3} Smpya=9333.333...S_{mpya} = 9333.333...

    Akiba mpya ya kila mwezi baada ya ongezeko ni 9333.33 Shilingi\boxed{\text{9333.33 Shilingi}}.


Swali la 2: Safari ya Martha

  • Kumbuka kuhusu swali: Maneno "4D\frac{4}{D} of her journey by bus, 22\frac{2}{2} by motorcycle" yanaweza kutafsiriwa kwa njia tofauti. Ikiwa 45\frac{4}{5} na 22\frac{2}{2} ni sehemu za safari nzima, basi jumla ya sehemu hizo (45+22=45+1=95\frac{4}{5} + \frac{2}{2} = \frac{4}{5} + 1 = \frac{9}{5}) inazidi 1, jambo ambalo haliwezekani kwa sehemu za safari moja. Kwa hivyo, tutachukulia kuwa 45\frac{4}{5} km na 22\frac{2}{2} km ni umbali halisi aliosafiri, licha ya neno "of her journey" ambalo kwa kawaida huashiria sehemu.

  • Step 1: Tambua umbali uliosafiri kwa basi na pikipiki. Umbali aliosafiri kwa basi = 45\frac{4}{5} km. Umbali aliosafiri kwa pikipiki = 22\frac{2}{2} km = 1 km.

  • Step 2: Badilisha jumla ya safari kuwa sehemu isiyofaa. Jumla ya safari = 473547\frac{3}{5} km.

    4735=(47×5)+35=235+35=2385 km47\frac{3}{5} = \frac{(47 \times 5) + 3}{5} = \frac{235 + 3}{5} = \frac{238}{5} \text{ km}
  • Step 3: Tafuta umbali aliotembea. Umbali aliotembea ni jumla ya safari kutoa umbali aliosafiri kwa basi na pikipiki.

    x=2385−45−1x = \frac{238}{5} - \frac{4}{5} - 1

    Ili kutoa sehemu hizi, tunahitaji madhehebu ya kawaida. Badilisha 1 kuwa 55\frac{5}{5}:

    x=2385−45−55x = \frac{238}{5} - \frac{4}{5} - \frac{5}{5} x=238−4−55x = \frac{238 - 4 - 5}{5} x=2295x = \frac{229}{5}

    Badilisha sehemu isiyofaa kuwa nambari mchanganyiko au desimali:

    x=4545 kmx = 45\frac{4}{5} \text{ km} x=45.8 kmx = 45.8 \text{ km}

    Umbali aliotembea ni 45.8 km\boxed{\text{45.8 km}}.

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