We read your photo as:

Write the amount 20,048,935 shillings in words. Calculate the length of a table top with an area of 1.5625 m². Determine the fraction of children in a town if women are 4/15 and men are 1/3 of the pop

Mathematics

ScanSolve AI Answer

Answers

2 parts
a

25\frac{2}{5}

b

144,000 women\text{144,000 women}

Step-by-step solution

5 steps

Here are the solutions to the problems:

1. Writing the amount in words

Step 1: Identify the given amount.
The amount is 20,048,935 shillings.

Step 2: Write the amount in words.
The amount in words is Twenty million, forty-eight thousand, nine hundred and thirty-five shillings.

2. Length of the table top

Step 1: Recall the formula for the area of a square.
The area AA of a square with side length ss is given by A=s2A = s^2.

Step 2: Substitute the given area and solve for ss.

1.5625 m2=s21.5625 \text{ m}^2 = s^2

To find ss, take the square root of the area:

s=1.5625s = \sqrt{1.5625} s=1.25 ms = 1.25 \text{ m}

The length of the table top is 1.25 m\boxed{\text{1.25 m}}.

3. Population fractions and numbers

Part a· 2 steps

Fraction representing children

  1. Find the combined fraction of women and men.

    Fraction of women =415= \frac{4}{15}
    Fraction of men =13= \frac{1}{3}
    Combined fraction =415+13=415+515=915=35= \frac{4}{15} + \frac{1}{3} = \frac{4}{15} + \frac{5}{15} = \frac{9}{15} = \frac{3}{5}

  2. Subtract the combined fraction from 1 to find the fraction of children.

    Fraction of children =1−35=55−35=25= 1 - \frac{3}{5} = \frac{5}{5} - \frac{3}{5} = \frac{2}{5}
    The fraction representing the children is 25\boxed{\frac{2}{5}}.

Part b

144,000 women\text{144,000 women}

Number of women in the town

  1. Let the total population be PP.

    Set up an equation based on the given information.
    Number of children =25P= \frac{2}{5} P
    Number of men =13P= \frac{1}{3} P
    Given that there are 36,000 more children than men:

    25P=13P+36000\frac{2}{5} P = \frac{1}{3} P + 36000
  2. Solve for PP.

    25P−13P=36000\frac{2}{5} P - \frac{1}{3} P = 36000

    Find a common denominator for 5 and 3, which is 15:

    615P−515P=36000\frac{6}{15} P - \frac{5}{15} P = 36000 115P=36000\frac{1}{15} P = 36000 P=36000×15P = 36000 \times 15 P=540000P = 540000
  3. Calculate the number of women.

    Number of women =415P=415×540000= \frac{4}{15} P = \frac{4}{15} \times 540000

    =4×54000015= 4 \times \frac{540000}{15} =4×36000= 4 \times 36000 =144000= 144000

    There are 144,000 women\boxed{\text{144,000 women}} in the town.

    **4. Determining the value of the expression

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp