A piece of land was sold for a certain amount of money. Musa received 25% of the money, Xmina received 30%, Kato received half of Xmina's share, and Sarah received 100,000,000 shillings. Calculate the

Let $M$ be the total amount of money obtained from the sale of the land.
Musa receives $25\%$ of $M$.
Xmina receives $30\%$ of $M$.
Kato receives half of what Xmina received, which is $\frac{1}{2} \times 30\% = 15\%$ of $M$.
Sarah receives the remainder, which is 100,000,000 shillings.

Since Sarah received the remainder, her share is $100\% - 70\% = 30\%$ of $M$.

We know that $30\%$ of $M$ is 100,000,000 shillings.

The total amount of money obtained from the sale of the land is $\boxed{\text{333,333,333.33 shillings}}$.

Musa received $25\%$ of $M$.

Xmina received $30\%$ of $M$.

Kato received $15\%$ of $M$.

Musa received $\boxed{\text{83,333,333.33 shillings}}$, Xmina received $\boxed{\text{100,000,000 shillings}}$, and Kato received $\boxed{\text{50,000,000 shillings}}$.

Musa visits every 15 days.
Xmina visits every 18 days.
Kato visits every 24 days.
Sarah visits every 30 days.
They all last visited on January 1st.

We need to find the LCM of $15, 18, 24,$ and 30.
Prime factorization:
$15 = 3 \times 5$
$18 = 2 \times 3^2$
$24 = 2^3 \times 3$
$30 = 2 \times 3 \times 5$

LCM is $2^3 \times 3^2 \times 5 = 8 \times 9 \times 5 = 360$.
So, they will all visit on the same day every 360 days.

Their last common visit was January 1st.
The next common visit will be 360 days after January 1st.
Number of days in January: 31
Number of days in February (2024 is a leap year, so 29 days): 29
Number of days in March: 31
Number of days in April: 30
Number of days in May: 31
Number of days in June: 30
Number of days in July: 31
Number of days in August: 31
Number of days in September: 30
Number of days in October: 31
Number of days in November: 30
Number of days in December: 31

Starting from January 1st:
January: 31 days (remaining $360 - 31 = 329$)
February: 29 days (remaining $329 - 29 = 300$)
March: 31 days (remaining $300 - 31 = 269$)
April: 30 days (remaining $269 - 30 = 239$)
May: 31 days (remaining $239 - 31 = 208$)
June: 30 days (remaining $208 - 30 = 178$)
July: 31 days (remaining $178 - 31 = 147$)
August: 31 days (remaining $147 - 31 = 116$)
September: 30 days (remaining $116 - 30 = 86$)
October: 31 days (remaining $86 - 31 = 55$)
November: 30 days (remaining $55 - 30 = 25$)
December: The $25$th day of December.

The next date when all four children will visit their parents on the same day is $\boxed{\text{December 25th}}$.

The parents plan to organize a thanksgiving lunch only if the next common visit falls before the end of March.

The next common visit date is December 25th.
The end of March is March 31st.

Since December 25th is after March 31st, the condition is not met.

The parents should $\boxed{\text{not organize the thanksgiving lunch before the end of March}}$.