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An item costs Rs. 400. During a festival sale, a company offers a sale discount that offers x% off on its regular price along with a discount coupon of 10%. The price of the item after using both the sale discount and the discount coupon, is Rs. 216. What is the value of x?

Mathematics

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यहां प्रश्न 1 का हल दिया गया है:

  1. दी गई जानकारी के अनुसार, वस्तु का मूल मूल्य (Marked Price) Rs.

    400 है। पहली छूट x%x\% है और दूसरी छूट (कूपन) 10%10\% है। वस्तु का अंतिम विक्रय मूल्य (Selling Price) Rs. 216 है।

  2. दो क्रमिक छूटों के बाद विक्रय मूल्य की गणना करने का सूत्र है

    विक्रय मूल्य=मूल मूल्य×(1−पहली छूट100)×(1−दूसरी छूट100)\text{विक्रय मूल्य} = \text{मूल मूल्य} \times \left(1 - \frac{\text{पहली छूट}}{100}\right) \times \left(1 - \frac{\text{दूसरी छूट}}{100}\right)

    दिए गए मानों को सूत्र में रखने पर:

    216=400×(1−x100)×(1−10100)216 = 400 \times \left(1 - \frac{x}{100}\right) \times \left(1 - \frac{10}{100}\right)

  3. समीकरण को सरल करें

    216=400×(1−x100)×(90100)216 = 400 \times \left(1 - \frac{x}{100}\right) \times \left(\frac{90}{100}\right) 216=400×(1−x100)×0.9216 = 400 \times \left(1 - \frac{x}{100}\right) \times 0.9 216=360×(1−x100)216 = 360 \times \left(1 - \frac{x}{100}\right)

  4. 1−x1001 - \frac{x}{100} के लिए हल करें

    216360=1−x100\frac{216}{360} = 1 - \frac{x}{100} 0.6=1−x1000.6 = 1 - \frac{x}{100}

  5. xx के लिए हल करें

    x100=1−0.6\frac{x}{100} = 1 - 0.6 x100=0.4\frac{x}{100} = 0.4 x=0.4×100x = 0.4 \times 100 x=40x = 40

    इसलिए, xx का मान 40 है।

    सही विकल्प है:

    (b) 40

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