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A trader bought a camera at a price that allowed for a 20% profit. He then sold it at a discount of 10% on the marked price of Ksh 2400. Find the cost price of the camera.

Mathematics

ScanSolve AI Answer

Answer

Ksh 1800\text{Ksh 1800}

a2−3ab−2b24a2−b2=a2−3ab−2b2(2a−b)(2a+b)\frac{a^2 - 3ab - 2b^2}{4a^2 - b^2} = \frac{a^2 - 3ab - 2b^2}{(2a - b)(2a + b)}

Step-by-step solution

6 steps
  1. Calculate the selling price (SP) of the camera.

    The marked price (MP) is Ksh 2400.
    The discount is 10% of the marked price.

    Discount amount=10%×2400=0.10×2400=240 Ksh\text{Discount amount} = 10\% \times 2400 = 0.10 \times 2400 = 240 \text{ Ksh}

    The selling price is the marked price minus the discount amount.

    SP=MP−Discount amount=2400−240=2160 Ksh\text{SP} = \text{MP} - \text{Discount amount} = 2400 - 240 = 2160 \text{ Ksh}
  2. Relate the selling price to the cost price (CP) and profit.

    The trader makes a profit of 20% on the cost price.
    This means the selling price is the cost price plus 20% of the cost price.

    SP=CP+20%×CP=CP+0.20×CP=1.20×CP\text{SP} = \text{CP} + 20\% \times \text{CP} = \text{CP} + 0.20 \times \text{CP} = 1.20 \times \text{CP}
  3. Determine the cost price (CP).

    We have the selling price from Step 1 and the relationship from Step 2.

    2160=1.20×CP2160 = 1.20 \times \text{CP}

    To find the cost price, divide the selling price by 1.20.

    CP=21601.20=2160012=1800 Ksh\text{CP} = \frac{2160}{1.20} = \frac{21600}{12} = 1800 \text{ Ksh}

    The cost price of the camera is Ksh 1800\boxed{\text{Ksh 1800}}.


  4. Factor the denominator.

    The denominator is a difference of squares, 4a2−b24a^2 - b^2.

    4a2−b2=(2a)2−b2=(2a−b)(2a+b)4a^2 - b^2 = (2a)^2 - b^2 = (2a - b)(2a + b)
  5. Attempt to factor the numerator.

    The numerator is a2−3ab−2b2a^2 - 3ab - 2b^2.
    To factor this quadratic expression, we look for two numbers that multiply to 1×(−2)=−21 \times (-2) = -2 and add up to −3-3. The integer pairs that multiply to -2 are (1, -2) and (-1, 2). Their sums are 1+(−2)=−11 + (-2) = -1 and −1+2=1-1 + 2 = 1. Neither sum is -3.
    Therefore, the numerator a2−3ab−2b2a^2 - 3ab - 2b^2 does not factor into simple linear terms with integer coefficients that would allow cancellation with the denominator's factors (2a−b)(2a-b) or (2a+b)(2a+b).

  6. Write the simplified expression.

    Since there are no common factors between the numerator and the denominator, the expression cannot be simplified further by cancellation. The most simplified form involves factoring the denominator.

    a2−3ab−2b24a2−b2=a2−3ab−2b2(2a−b)(2a+b)\frac{a^2 - 3ab - 2b^2}{4a^2 - b^2} = \boxed{\frac{a^2 - 3ab - 2b^2}{(2a - b)(2a + b)}}
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