The area of a rectangular farm is 7462m². The width of the farm is 82m. Use logarithm tables to determine the length of the farm.

The area of a rectangle ($A$) is given by the formula $A = \text{length} \times \text{width}$.
Given $A = 7462 \text{ m}^2$ and width $w = 82 \text{ m}$.
We need to find the length $l$.

$$l = \frac{A}{w} = \frac{7462}{82}$$

To use logarithm tables, we convert the division into a subtraction of logarithms.

$$\log l = \log\left(\frac{7462}{82}\right) = \log(7462) - \log(82)$$

The characteristic of $\log(7462)$ is 3 (since $7462 = 7.462 \times 10^3$).
From logarithm tables, the mantissa for 746 is 0.8727. The mean difference for 2 is 1.
So, the mantissa for 7462 is $0.8727 + 0.0001 = 0.8728$.

$$\log(7462) = 3.8728$$

The characteristic of $\log(82)$ is 1 (since $82 = 8.2 \times 10^1$).
From logarithm tables, the mantissa for 820 is 0.9138.

$$\log(82) = 1.9138$$

$$\log l = 3.8728 - 1.9138$$ $$\log l = 1.9590$$

The characteristic is 1, which means the number has two digits before the decimal point.
From antilogarithm tables, the antilog of 0.9590 is approximately 9.099.
Multiplying by $10^1$ (due to the characteristic of 1):

$$l = 9.099 \times 10^1 = 90.99$$

The length of the farm is approximately 90.99 m.

$\boxed{90.99 \text{ m}}$