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ATTEMPT ALL THE QUESTIONS AT THE BACK OF THE PAGE The table below shows income tax rates for the year 2006

Mathematics

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2 parts
a

a) ∠ABD=31∘\text{a) } \angle ABD = 31^\circ

b

b) ∠CBD=37∘\text{b) } \angle CBD = 37^\circ

Step-by-step solution

6 steps

Huu hapa ni ufumbuzi wa swali la 3:

Part a· 5 steps

Kokotoa ukubwa wa ∠ABD\angle ABD.

  1. Tafuta ∠BAD\angle BAD.

    Kwa kuwa EADF ni mstari ulionyooka, jumla ya pembe kwenye mstari ni 180∘180^\circ.

    ∠BAD+∠BAE=180∘\angle BAD + \angle BAE = 180^\circ

    Tunajua ∠BAE=98∘\angle BAE = 98^\circ.

    ∠BAD=180∘−98∘=82∘\angle BAD = 180^\circ - 98^\circ = 82^\circ
  2. Tafuta ∠ABC\angle ABC.

    Pembe ya nje ya quadrilateral ya mzunguko ni sawa na pembe ya ndani iliyo kinyume.

    ∠ABC=∠CDF\angle ABC = \angle CDF

    Tunajua ∠CDF=68∘\angle CDF = 68^\circ.

    ∠ABC=68∘\angle ABC = 68^\circ
  3. Tafuta ∠ADC\angle ADC.

    Jumla ya pembe zinazopingana katika quadrilateral ya mzunguko ni 180∘180^\circ.

    ∠ABC+∠ADC=180∘\angle ABC + \angle ADC = 180^\circ 68∘+∠ADC=180∘68^\circ + \angle ADC = 180^\circ ∠ADC=180∘−68∘=112∘\angle ADC = 180^\circ - 68^\circ = 112^\circ
  4. Tafuta ∠ADB\angle ADB.

    Tunajua ∠ADC=112∘\angle ADC = 112^\circ na ∠BDC=45∘\angle BDC = 45^\circ.

    ∠ADB=∠ADC−∠BDC\angle ADB = \angle ADC - \angle BDC ∠ADB=112∘−45∘=67∘\angle ADB = 112^\circ - 45^\circ = 67^\circ
  5. Tafuta ∠ABD\angle ABD katika △ABD\triangle ABD.

    Jumla ya pembe katika pembetatu ni 180∘180^\circ.

    ∠ABD+∠BAD+∠ADB=180∘\angle ABD + \angle BAD + \angle ADB = 180^\circ ∠ABD+82∘+67∘=180∘\angle ABD + 82^\circ + 67^\circ = 180^\circ ∠ABD+149∘=180∘\angle ABD + 149^\circ = 180^\circ ∠ABD=180∘−149∘=31∘\angle ABD = 180^\circ - 149^\circ = 31^\circ

    Kwa hivyo, a) ∠ABD=31∘\boxed{\text{a) } \angle ABD = 31^\circ}.

Part b

b) ∠CBD=37∘\text{b) } \angle CBD = 37^\circ

Kokotoa ukubwa wa ∠CBD\angle CBD.

  1. Tafuta ∠CBD\angle CBD.

    Tunajua ∠ABC=68∘\angle ABC = 68^\circ na ∠ABD=31∘\angle ABD = 31^\circ.

    ∠CBD=∠ABC−∠ABD\angle CBD = \angle ABC - \angle ABD ∠CBD=68∘−31∘=37∘\angle CBD = 68^\circ - 31^\circ = 37^\circ

    Kwa hivyo, b) ∠CBD=37∘\boxed{\text{b) } \angle CBD = 37^\circ}.

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