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Match the temperatures with the times.

Mathematics

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Step-by-step solution

3 steps
  1. Average rate of temperature change from 2:00 a.m.

    to 11:00 a.m.

    Formula:

    Average rate=ΔTΔt\text{Average rate} = \frac{\Delta T}{\Delta t}

    T2:00 a.m.=−4∘CT_{2:00~\rm a.m.} = -4^\circ \rm C
    T11:00 a.m.=14∘CT_{11:00~\rm a.m.} = 14^\circ \rm C

    ΔT=14∘C−(−4∘C)=18∘C\Delta T = 14^\circ \rm C - (-4^\circ \rm C) = 18^\circ \rm C

    Δt=11:00 a.m.−2:00 a.m.=9 h\Delta t = 11:00~\rm a.m. - 2:00~\rm a.m. = 9~\rm h

    Average rate=18∘C9 h=2∘C/h\text{Average rate} = \frac{18^\circ \rm C}{9~\rm h} = 2^\circ \rm C/\rm h

    2^\circ C/h

  2. Average rate of temperature change from 11:00 a.m.

    to 2:00 p.m.

    Formula:

    Average rate=ΔTΔt\text{Average rate} = \frac{\Delta T}{\Delta t}

    T11:00 a.m.=14∘CT_{11:00~\rm a.m.} = 14^\circ \rm C
    T2:00 p.m.=−2∘CT_{2:00~\rm p.m.} = -2^\circ \rm C

    ΔT=−2∘C−14∘C=−16∘C\Delta T = -2^\circ \rm C - 14^\circ \rm C = -16^\circ \rm C

    Δt=2:00 p.m.−11:00 a.m.=3 h\Delta t = 2:00~\rm p.m. - 11:00~\rm a.m. = 3~\rm h

    Average rate=−16∘C3 h=−163∘C/h≈−5.33∘C/h\text{Average rate} = \frac{-16^\circ \rm C}{3~\rm h} = -\frac{16}{3}^\circ \rm C/\rm h \approx -5.33^\circ \rm C/\rm h

    -\frac{16}{3}^\circ C/h

  3. Average rate of temperature change from 2:00 a.m.

    to 2:00 p.m.

    Formula:

    Average rate=ΔTΔt\text{Average rate} = \frac{\Delta T}{\Delta t}

    $T_{2:00~\rm a.m.} = -4^\circ \rm

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